Aptitude

True Discount – 1

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Jun 10, 2019

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Last Updated on Mar 16, 2023

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Name: True Discount – 1

Subject: Numerical Aptitude ( संख्यात्मक अभियोगिता)

Topic: True Discount – 1

Questions: 10 Objective Type Questions

Time Allowed: 25 Minutes

Language: English

Important for: Police Exam, SSC ( CGL, CHSL, GD etc), State PCS, UPSC, Railway, IBPS Clerk, IBPS RRB, SBI Clerk, Engineering Entrance exam, समूह ग आदि |

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Question 1 of 10

1. Question
1 points
The present worth of Rs. 2310 due \(2\frac{1}{2}\) years hence, the rate of interest being 15% per annum, is
- Rs. 1750
- Rs. 1680
- Rs. 1840
- Rs. 1443.75
Correct

\(P.W. = Rs. \left [ \frac{100\times2310}{100+\left ( 15\times\frac{5}{2} \right )} \right ]= Rs. 1680\)

Incorrect

\(P.W. = Rs. \left [ \frac{100\times2310}{100+\left ( 15\times\frac{5}{2} \right )} \right ]= Rs. 1680\)

Unattempted

\(P.W. = Rs. \left [ \frac{100\times2310}{100+\left ( 15\times\frac{5}{2} \right )} \right ]= Rs. 1680\)
Question 2 of 10

2. Question
1 points
If the discount on a sum due 2 years hence at 14% per annum be Rs. 168, the sum due is:
- Rs. 768
- Rs. 968
- Rs. 1960
- Rs. 2400
Correct

\(P.W. = \frac{100 \times T.D.}{R \times T}=\frac{100 \times 168}{14 \times 2}= 600\)
Sum = (P.W. + T.D.)= Rs. (600+168)= Rs. 768.

Incorrect

\(P.W. = \frac{100 \times T.D.}{R \times T}=\frac{100 \times 168}{14 \times 2}= 600\)
Sum = (P.W. + T.D.)= Rs. (600+168)= Rs. 768.

Unattempted

\(P.W. = \frac{100 \times T.D.}{R \times T}=\frac{100 \times 168}{14 \times 2}= 600\)
Sum = (P.W. + T.D.)= Rs. (600+168)= Rs. 768.
Question 3 of 10

3. Question
1 points
The true discount on Rs. 2562 due 4 months hence is Rs. 122. The rate percent is:
- 12%
- 13.5%
- 15%
- 14%
Correct

P.W. = Rs. (2562-122)= Rs. 2440.
S.I. on Rs. 2440 for 4 months is Rs. 122.
\(Rate= \left ( \frac{100\times122}{2440\times\frac{1}{3}} \right )\) = 15%

Incorrect

P.W. = Rs. (2562-122)= Rs. 2440.
S.I. on Rs. 2440 for 4 months is Rs. 122.
\(Rate= \left ( \frac{100\times122}{2440\times\frac{1}{3}} \right )\) = 15%

Unattempted

P.W. = Rs. (2562-122)= Rs. 2440.
S.I. on Rs. 2440 for 4 months is Rs. 122.
\(Rate= \left ( \frac{100\times122}{2440\times\frac{1}{3}} \right )\) = 15%
Question 4 of 10

4. Question
1 points
The true discount on Rs. 1760 due after a certain time at 12% per annum is Rs. 160. The time after which it is due is:
- 6 months
- 8 months
- 9 months
- 10 months
Correct

P.W. = Rs. (1760-160)= Rs. 1600
S.I. on Rs. 1600 at 12% is Rs. 160
Time = \(\left ( \frac{100\times160}{1600\times12} \right ) = \frac{5}{6}years = \left ( \frac{5}{6}\times12 \right )\) months = 10 months.

Incorrect

P.W. = Rs. (1760-160)= Rs. 1600
S.I. on Rs. 1600 at 12% is Rs. 160
Time = \(\left ( \frac{100\times160}{1600\times12} \right ) = \frac{5}{6}years = \left ( \frac{5}{6}\times12 \right )\) months = 10 months.

Unattempted

P.W. = Rs. (1760-160)= Rs. 1600
S.I. on Rs. 1600 at 12% is Rs. 160
Time = \(\left ( \frac{100\times160}{1600\times12} \right ) = \frac{5}{6}years = \left ( \frac{5}{6}\times12 \right )\) months = 10 months.
Question 5 of 10

5. Question
1 points
The true discount on a bill due 9 months hence at 16% per annum is Rs. 960 due 2 years hence. If the rate of interest is the same in both cases, it is:
- Rs. 1386
- Rs. 1764
- Rs. 1575
- Rs. 2268
Correct

Let P.W. be Rs. x. Then, S.I. on Rs. x at 16% for 9 months = Rs. 189.
\(x\times16\times\frac{9}{12}\times\frac{1}{100} = 189 or x = 1575.\)
P.W. = Rs. 1575.
sum due = P.W. + T.D. on Rs. (1575 + 189)= Rs 1764.

Incorrect

Let P.W. be Rs. x. Then, S.I. on Rs. x at 16% for 9 months = Rs. 189.
\(x\times16\times\frac{9}{12}\times\frac{1}{100} = 189 or x = 1575.\)
P.W. = Rs. 1575.
sum due = P.W. + T.D. on Rs. (1575 + 189)= Rs 1764.

Unattempted

Let P.W. be Rs. x. Then, S.I. on Rs. x at 16% for 9 months = Rs. 189.
\(x\times16\times\frac{9}{12}\times\frac{1}{100} = 189 or x = 1575.\)
P.W. = Rs. 1575.
sum due = P.W. + T.D. on Rs. (1575 + 189)= Rs 1764.
Question 6 of 10

6. Question
1 points
The simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 85 and Rs. 80 respectively. The sum is:
- Rs. 1800
- Rs. 1450
- Rs. 1360
- Rs. 6800
Correct

Sum =\(\left ( \frac{S.I. \times T.D. }{(S.I.)-(T.D.)}\right )= \frac{85 \times 80}{(85-80)}= Rs. 1360\)

Incorrect

Sum =\(\left ( \frac{S.I. \times T.D. }{(S.I.)-(T.D.)}\right )= \frac{85 \times 80}{(85-80)}= Rs. 1360\)

Unattempted

Sum =\(\left ( \frac{S.I. \times T.D. }{(S.I.)-(T.D.)}\right )= \frac{85 \times 80}{(85-80)}= Rs. 1360\)
Question 7 of 10

7. Question
1 points
A man wants to sell his scooter. There are two offers, one at Rs. 12,000 cash and the other at a credit of Rs. 12,880 to be paid after 8 months, money being at 18% per annum. Which is the better offer?
- Rs. 12,000 in cash
- Rs. 12,880 at credit
- Both are equally good
- None of these
Correct

P.W. of Rs. 12,880 due 8 months hence
= Rs. \(\left [ \frac{12880\times100}{100+\left ( 18\times\frac{8}{12} \right )} \right ] = Rs. \left ( \frac{12880\times100}{112} \right ) = Rs. 11500\)
Clearly, Rs. 12,000 in cash is a better offer.

Incorrect

P.W. of Rs. 12,880 due 8 months hence
= Rs. \(\left [ \frac{12880\times100}{100+\left ( 18\times\frac{8}{12} \right )} \right ] = Rs. \left ( \frac{12880\times100}{112} \right ) = Rs. 11500\)
Clearly, Rs. 12,000 in cash is a better offer.

Unattempted

P.W. of Rs. 12,880 due 8 months hence
= Rs. \(\left [ \frac{12880\times100}{100+\left ( 18\times\frac{8}{12} \right )} \right ] = Rs. \left ( \frac{12880\times100}{112} \right ) = Rs. 11500\)
Clearly, Rs. 12,000 in cash is a better offer.
Question 8 of 10

8. Question
1 points
A trader owes a merchant Rs. 10,0028 due 1 year hence. The trader wants to settle the account after 3 months. If the rate of interest is 12% per annum, how much cash should he pay?
- Rs. 9025.20
- Rs. 9200
- Rs. 9600
- Rs. 9560
Correct

Required money = P.W. of Rs. 10028 due 9 months hence
\(= Rs. \left [ \frac{10028\times100}{100+\left ( 12\times\frac{9}{12} \right )} \right ]= Rs. 9200\)

Incorrect

Required money = P.W. of Rs. 10028 due 9 months hence
\(= Rs. \left [ \frac{10028\times100}{100+\left ( 12\times\frac{9}{12} \right )} \right ]= Rs. 9200\)

Unattempted

Required money = P.W. of Rs. 10028 due 9 months hence
\(= Rs. \left [ \frac{10028\times100}{100+\left ( 12\times\frac{9}{12} \right )} \right ]= Rs. 9200\)
Question 9 of 10

9. Question
1 points
A man buys a watch for Rs. 1950 in cash and sells it for Rs. 2200 at a credit of 1 year. If the rate of interest is 10% per annum, the man:
- gains Rs. 55
- gains Rs. 50
- loses Rs. 30
- gains Rs. 30
Correct

S.P. = P.W. of Rs. 2200 due 1 year hence = Rs. \(= Rs. \left [ \frac{2200\times100}{100+ (10\times1)} \right ]= Rs. 2000\)
Gain = Rs. (2000-1950)= Rs. 50

Incorrect

S.P. = P.W. of Rs. 2200 due 1 year hence = Rs. \(= Rs. \left [ \frac{2200\times100}{100+ (10\times1)} \right ]= Rs. 2000\)
Gain = Rs. (2000-1950)= Rs. 50

Unattempted

S.P. = P.W. of Rs. 2200 due 1 year hence = Rs. \(= Rs. \left [ \frac{2200\times100}{100+ (10\times1)} \right ]= Rs. 2000\)
Gain = Rs. (2000-1950)= Rs. 50
Question 10 of 10

10. Question
1 points
A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, them the man has a gain of:
- 0%
- 5%
- 7.5%
- 10%
Correct

C.P. = Rs. 3000. S.P. = Rs \(= Rs. \left [ \frac{3600\times100}{100+ (10\times2)} \right ]= Rs. 3000\) Gain = 0%

Incorrect

C.P. = Rs. 3000. S.P. = Rs \(= Rs. \left [ \frac{3600\times100}{100+ (10\times2)} \right ]= Rs. 3000\) Gain = 0%

Unattempted

C.P. = Rs. 3000. S.P. = Rs \(= Rs. \left [ \frac{3600\times100}{100+ (10\times2)} \right ]= Rs. 3000\) Gain = 0%