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Name: True Discount – 1
Subject: Numerical Aptitude ( संख्यात्मक अभियोगिता)
Topic: True Discount – 1
Questions: 10 Objective Type Questions
Time Allowed: 25 Minutes
Language: English
Important for: Police Exam, SSC ( CGL, CHSL, GD etc), State PCS, UPSC, Railway, IBPS Clerk, IBPS RRB, SBI Clerk, Engineering Entrance exam, समूह ग आदि 
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 Question 1 of 10
1. Question
1 pointsThe present worth of Rs. 2310 due \(2\frac{1}{2}\) years hence, the rate of interest being 15% per annum, is
Correct\(P.W. = Rs. \left [ \frac{100\times2310}{100+\left ( 15\times\frac{5}{2} \right )} \right ]= Rs. 1680\)
Incorrect\(P.W. = Rs. \left [ \frac{100\times2310}{100+\left ( 15\times\frac{5}{2} \right )} \right ]= Rs. 1680\)
Unattempted\(P.W. = Rs. \left [ \frac{100\times2310}{100+\left ( 15\times\frac{5}{2} \right )} \right ]= Rs. 1680\)
 Question 2 of 10
2. Question
1 pointsIf the discount on a sum due 2 years hence at 14% per annum be Rs. 168, the sum due is:
Correct\(P.W. = \frac{100 \times T.D.}{R \times T}=\frac{100 \times 168}{14 \times 2}= 600\)
Sum = (P.W. + T.D.)= Rs. (600+168)= Rs. 768.Incorrect\(P.W. = \frac{100 \times T.D.}{R \times T}=\frac{100 \times 168}{14 \times 2}= 600\)
Sum = (P.W. + T.D.)= Rs. (600+168)= Rs. 768.Unattempted\(P.W. = \frac{100 \times T.D.}{R \times T}=\frac{100 \times 168}{14 \times 2}= 600\)
Sum = (P.W. + T.D.)= Rs. (600+168)= Rs. 768.  Question 3 of 10
3. Question
1 pointsThe true discount on Rs. 2562 due 4 months hence is Rs. 122. The rate percent is:
CorrectP.W. = Rs. (2562122)= Rs. 2440.
S.I. on Rs. 2440 for 4 months is Rs. 122.
\(Rate= \left ( \frac{100\times122}{2440\times\frac{1}{3}} \right )\) = 15%IncorrectP.W. = Rs. (2562122)= Rs. 2440.
S.I. on Rs. 2440 for 4 months is Rs. 122.
\(Rate= \left ( \frac{100\times122}{2440\times\frac{1}{3}} \right )\) = 15%UnattemptedP.W. = Rs. (2562122)= Rs. 2440.
S.I. on Rs. 2440 for 4 months is Rs. 122.
\(Rate= \left ( \frac{100\times122}{2440\times\frac{1}{3}} \right )\) = 15%  Question 4 of 10
4. Question
1 pointsThe true discount on Rs. 1760 due after a certain time at 12% per annum is Rs. 160. The time after which it is due is:
CorrectP.W. = Rs. (1760160)= Rs. 1600
S.I. on Rs. 1600 at 12% is Rs. 160
Time = \(\left ( \frac{100\times160}{1600\times12} \right ) = \frac{5}{6}years = \left ( \frac{5}{6}\times12 \right )\) months = 10 months.IncorrectP.W. = Rs. (1760160)= Rs. 1600
S.I. on Rs. 1600 at 12% is Rs. 160
Time = \(\left ( \frac{100\times160}{1600\times12} \right ) = \frac{5}{6}years = \left ( \frac{5}{6}\times12 \right )\) months = 10 months.UnattemptedP.W. = Rs. (1760160)= Rs. 1600
S.I. on Rs. 1600 at 12% is Rs. 160
Time = \(\left ( \frac{100\times160}{1600\times12} \right ) = \frac{5}{6}years = \left ( \frac{5}{6}\times12 \right )\) months = 10 months.  Question 5 of 10
5. Question
1 pointsThe true discount on a bill due 9 months hence at 16% per annum is Rs. 960 due 2 years hence. If the rate of interest is the same in both cases, it is:
CorrectLet P.W. be Rs. x. Then, S.I. on Rs. x at 16% for 9 months = Rs. 189.
\(x\times16\times\frac{9}{12}\times\frac{1}{100} = 189 or x = 1575.\)
P.W. = Rs. 1575.
sum due = P.W. + T.D. on Rs. (1575 + 189)= Rs 1764.IncorrectLet P.W. be Rs. x. Then, S.I. on Rs. x at 16% for 9 months = Rs. 189.
\(x\times16\times\frac{9}{12}\times\frac{1}{100} = 189 or x = 1575.\)
P.W. = Rs. 1575.
sum due = P.W. + T.D. on Rs. (1575 + 189)= Rs 1764.UnattemptedLet P.W. be Rs. x. Then, S.I. on Rs. x at 16% for 9 months = Rs. 189.
\(x\times16\times\frac{9}{12}\times\frac{1}{100} = 189 or x = 1575.\)
P.W. = Rs. 1575.
sum due = P.W. + T.D. on Rs. (1575 + 189)= Rs 1764.  Question 6 of 10
6. Question
1 pointsThe simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 85 and Rs. 80 respectively. The sum is:
CorrectSum =\(\left ( \frac{S.I. \times T.D. }{(S.I.)(T.D.)}\right )= \frac{85 \times 80}{(8580)}= Rs. 1360\)
IncorrectSum =\(\left ( \frac{S.I. \times T.D. }{(S.I.)(T.D.)}\right )= \frac{85 \times 80}{(8580)}= Rs. 1360\)
UnattemptedSum =\(\left ( \frac{S.I. \times T.D. }{(S.I.)(T.D.)}\right )= \frac{85 \times 80}{(8580)}= Rs. 1360\)
 Question 7 of 10
7. Question
1 pointsA man wants to sell his scooter. There are two offers, one at Rs. 12,000 cash and the other at a credit of Rs. 12,880 to be paid after 8 months, money being at 18% per annum. Which is the better offer?
CorrectP.W. of Rs. 12,880 due 8 months hence
= Rs. \(\left [ \frac{12880\times100}{100+\left ( 18\times\frac{8}{12} \right )} \right ] = Rs. \left ( \frac{12880\times100}{112} \right ) = Rs. 11500\)
Clearly, Rs. 12,000 in cash is a better offer.IncorrectP.W. of Rs. 12,880 due 8 months hence
= Rs. \(\left [ \frac{12880\times100}{100+\left ( 18\times\frac{8}{12} \right )} \right ] = Rs. \left ( \frac{12880\times100}{112} \right ) = Rs. 11500\)
Clearly, Rs. 12,000 in cash is a better offer.UnattemptedP.W. of Rs. 12,880 due 8 months hence
= Rs. \(\left [ \frac{12880\times100}{100+\left ( 18\times\frac{8}{12} \right )} \right ] = Rs. \left ( \frac{12880\times100}{112} \right ) = Rs. 11500\)
Clearly, Rs. 12,000 in cash is a better offer.  Question 8 of 10
8. Question
1 pointsA trader owes a merchant Rs. 10,0028 due 1 year hence. The trader wants to settle the account after 3 months. If the rate of interest is 12% per annum, how much cash should he pay?
CorrectRequired money = P.W. of Rs. 10028 due 9 months hence
\(= Rs. \left [ \frac{10028\times100}{100+\left ( 12\times\frac{9}{12} \right )} \right ]= Rs. 9200\)IncorrectRequired money = P.W. of Rs. 10028 due 9 months hence
\(= Rs. \left [ \frac{10028\times100}{100+\left ( 12\times\frac{9}{12} \right )} \right ]= Rs. 9200\)UnattemptedRequired money = P.W. of Rs. 10028 due 9 months hence
\(= Rs. \left [ \frac{10028\times100}{100+\left ( 12\times\frac{9}{12} \right )} \right ]= Rs. 9200\)  Question 9 of 10
9. Question
1 pointsA man buys a watch for Rs. 1950 in cash and sells it for Rs. 2200 at a credit of 1 year. If the rate of interest is 10% per annum, the man:
CorrectS.P. = P.W. of Rs. 2200 due 1 year hence = Rs. \(= Rs. \left [ \frac{2200\times100}{100+ (10\times1)} \right ]= Rs. 2000\)
Gain = Rs. (20001950)= Rs. 50IncorrectS.P. = P.W. of Rs. 2200 due 1 year hence = Rs. \(= Rs. \left [ \frac{2200\times100}{100+ (10\times1)} \right ]= Rs. 2000\)
Gain = Rs. (20001950)= Rs. 50UnattemptedS.P. = P.W. of Rs. 2200 due 1 year hence = Rs. \(= Rs. \left [ \frac{2200\times100}{100+ (10\times1)} \right ]= Rs. 2000\)
Gain = Rs. (20001950)= Rs. 50  Question 10 of 10
10. Question
1 pointsA man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, them the man has a gain of:
CorrectC.P. = Rs. 3000. S.P. = Rs \(= Rs. \left [ \frac{3600\times100}{100+ (10\times2)} \right ]= Rs. 3000\) Gain = 0%
IncorrectC.P. = Rs. 3000. S.P. = Rs \(= Rs. \left [ \frac{3600\times100}{100+ (10\times2)} \right ]= Rs. 3000\) Gain = 0%
UnattemptedC.P. = Rs. 3000. S.P. = Rs \(= Rs. \left [ \frac{3600\times100}{100+ (10\times2)} \right ]= Rs. 3000\) Gain = 0%