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Name: Odd Man Out and Series – 1
Subject: Reasoning (तार्किक अभियोगिता)
Topic: Odd Man Out and Series – 1
Questions: 10 Objective Type Questions
Time Allowed: 25 Minutes
Language: English
Important for: Police Exam, SSC ( CGL, CHSL, GD etc), State PCS, UPSC, Railway, IBPS Clerk, IBPS RRB, SBI Clerk, Engineering Entrance exam, समूह ग आदि 
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Pos.  Name  Entered on  Points  Result 

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Question 1 of 10
1. Question
1 pointsDirections (0110): Find the odd man out.
3, 5, 7, 12, 17, 19
Correct
Each of the numbers except 12, is a prime number.
Incorrect
Each of the numbers except 12, is a prime number.
Unattempted
Each of the numbers except 12, is a prime number.

Question 2 of 10
2. Question
1 points1, 4, 9, 16, 23, 25, 36
Find the odd man out.
Correct
Each of the given numbers except 23, is a perfect square.
Incorrect
Each of the given numbers except 23, is a perfect square.
Unattempted
Each of the given numbers except 23, is a perfect square.

Question 3 of 10
3. Question
1 points41, 43, 47, 53, 61, 71, 73, 81
Find the odd man out.
Correct
Each of the numbers except 81, is a prime number.
Incorrect
Each of the numbers except 81, is a prime number.
Unattempted
Each of the numbers except 81, is a prime number.

Question 4 of 10
4. Question
1 points385, 462, 572, 396, 427, 671, 264
Find the odd man out.
Correct
In each number except 427, the middle digit is the sum of the other two.
Incorrect
In each number except 427, the middle digit is the sum of the other two.
Unattempted
In each number except 427, the middle digit is the sum of the other two.

Question 5 of 10
5. Question
1 points331, 482, 551, 263, 383, 242, 111
Find the odd man out.
Correct
In each number except 383, the product of first and third digit is the middle one.
Incorrect
In each number except 383, the product of first and third digit is the middle one.
Unattempted
In each number except 383, the product of first and third digit is the middle one.

Question 6 of 10
6. Question
1 points2, 5, 10, 17, 26, 37, 50, 64
Find the odd man out.
Correct
The pattern is \(x^{2} + 1\), where x = 1, 2, 3, 4, 5, 6, 7, 8 etc. But, 64 is out of pattern.
Incorrect
The pattern is \(x^{2} + 1\), where x = 1, 2, 3, 4, 5, 6, 7, 8 etc. But, 64 is out of pattern.
Unattempted
The pattern is \(x^{2} + 1\), where x = 1, 2, 3, 4, 5, 6, 7, 8 etc. But, 64 is out of pattern.

Question 7 of 10
7. Question
1 points253, 136, 352, 460, 324, 631, 244
Correct
Sum of the digits in each number, except 324 is 10.
Incorrect
Sum of the digits in each number, except 324 is 10.
Unattempted
Sum of the digits in each number, except 324 is 10.

Question 8 of 10
8. Question
1 points4, 5, 7, 10, 14, 18, 25, 32
Find the odd man out.
Correct
2^{nd} = (1^{st}+1); 3^{rd} = (2^{nd} + 2); 4^{th} = (3^{rd} + 3); 5^{th} = (4^{th} + 4)
But, 18 = 6^{th} \(\neq 5th + 5 =14 + 5= 19\)Incorrect
2^{nd} = (1^{st}+1); 3^{rd} = (2^{nd} + 2); 4^{th} = (3^{rd} + 3); 5^{th} = (4^{th} + 4)
But, 18 = 6^{th} \(\neq 5th + 5 =14 + 5= 19\)Unattempted
2^{nd} = (1^{st}+1); 3^{rd} = (2^{nd} + 2); 4^{th} = (3^{rd} + 3); 5^{th} = (4^{th} + 4)
But, 18 = 6^{th} \(\neq 5th + 5 =14 + 5= 19\) 
Question 9 of 10
9. Question
1 points2, 5, 10, 50, 500, 5000
Find the odd man out.
Correct
Pattern is \(1^{st}\times2nd = 3^{rd}; 2^{nd}\times3rd= 4^{th}; 3^{rd}\times4th = 5^{th}\)
But, \(4^{th}\times5th = 50\times500 = 25000\neq5000=6^{th}\)Incorrect
Pattern is \(1^{st}\times2nd = 3^{rd}; 2^{nd}\times3rd= 4^{th}; 3^{rd}\times4th = 5^{th}\)
But, \(4^{th}\times5th = 50\times500 = 25000\neq5000=6^{th}\)Unattempted
Pattern is \(1^{st}\times2nd = 3^{rd}; 2^{nd}\times3rd= 4^{th}; 3^{rd}\times4th = 5^{th}\)
But, \(4^{th}\times5th = 50\times500 = 25000\neq5000=6^{th}\) 
Question 10 of 10
10. Question
1 points41, 43, 47, 53, 61, 71, 73, 81
Find the odd man out.
Correct
Each of the numbers except 81, is a prime number.
Incorrect
Each of the numbers except 81, is a prime number.
Unattempted
Each of the numbers except 81, is a prime number.