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Name: Odd Man Out and Series – 1
Subject: Reasoning (तार्किक अभियोगिता)
Topic: Odd Man Out and Series – 1
Questions: 10 Objective Type Questions
Time Allowed: 25 Minutes
Language: English
Important for: Police Exam, SSC ( CGL, CHSL, GD etc), State PCS, UPSC, Railway, IBPS Clerk, IBPS RRB, SBI Clerk, Engineering Entrance exam, समूह ग आदि 
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 Review
 Question 1 of 10
1. Question
1 pointsDirections (0110): Find the odd man out.
3, 5, 7, 12, 17, 19
CorrectEach of the numbers except 12, is a prime number.
IncorrectEach of the numbers except 12, is a prime number.
UnattemptedEach of the numbers except 12, is a prime number.
 Question 2 of 10
2. Question
1 points1, 4, 9, 16, 23, 25, 36
Find the odd man out.
CorrectEach of the given numbers except 23, is a perfect square.
IncorrectEach of the given numbers except 23, is a perfect square.
UnattemptedEach of the given numbers except 23, is a perfect square.
 Question 3 of 10
3. Question
1 points41, 43, 47, 53, 61, 71, 73, 81
Find the odd man out.
CorrectEach of the numbers except 81, is a prime number.
IncorrectEach of the numbers except 81, is a prime number.
UnattemptedEach of the numbers except 81, is a prime number.
 Question 4 of 10
4. Question
1 points385, 462, 572, 396, 427, 671, 264
Find the odd man out.
CorrectIn each number except 427, the middle digit is the sum of the other two.
IncorrectIn each number except 427, the middle digit is the sum of the other two.
UnattemptedIn each number except 427, the middle digit is the sum of the other two.
 Question 5 of 10
5. Question
1 points331, 482, 551, 263, 383, 242, 111
Find the odd man out.
CorrectIn each number except 383, the product of first and third digit is the middle one.
IncorrectIn each number except 383, the product of first and third digit is the middle one.
UnattemptedIn each number except 383, the product of first and third digit is the middle one.
 Question 6 of 10
6. Question
1 points2, 5, 10, 17, 26, 37, 50, 64
Find the odd man out.
CorrectThe pattern is \(x^{2} + 1\), where x = 1, 2, 3, 4, 5, 6, 7, 8 etc. But, 64 is out of pattern.
IncorrectThe pattern is \(x^{2} + 1\), where x = 1, 2, 3, 4, 5, 6, 7, 8 etc. But, 64 is out of pattern.
UnattemptedThe pattern is \(x^{2} + 1\), where x = 1, 2, 3, 4, 5, 6, 7, 8 etc. But, 64 is out of pattern.
 Question 7 of 10
7. Question
1 points253, 136, 352, 460, 324, 631, 244
CorrectSum of the digits in each number, except 324 is 10.
IncorrectSum of the digits in each number, except 324 is 10.
UnattemptedSum of the digits in each number, except 324 is 10.
 Question 8 of 10
8. Question
1 points4, 5, 7, 10, 14, 18, 25, 32
Find the odd man out.
Correct2^{nd} = (1^{st}+1); 3^{rd} = (2^{nd} + 2); 4^{th} = (3^{rd} + 3); 5^{th} = (4^{th} + 4)
But, 18 = 6^{th} \(\neq 5th + 5 =14 + 5= 19\)Incorrect2^{nd} = (1^{st}+1); 3^{rd} = (2^{nd} + 2); 4^{th} = (3^{rd} + 3); 5^{th} = (4^{th} + 4)
But, 18 = 6^{th} \(\neq 5th + 5 =14 + 5= 19\)Unattempted2^{nd} = (1^{st}+1); 3^{rd} = (2^{nd} + 2); 4^{th} = (3^{rd} + 3); 5^{th} = (4^{th} + 4)
But, 18 = 6^{th} \(\neq 5th + 5 =14 + 5= 19\)  Question 9 of 10
9. Question
1 points2, 5, 10, 50, 500, 5000
Find the odd man out.
CorrectPattern is \(1^{st}\times2nd = 3^{rd}; 2^{nd}\times3rd= 4^{th}; 3^{rd}\times4th = 5^{th}\)
But, \(4^{th}\times5th = 50\times500 = 25000\neq5000=6^{th}\)IncorrectPattern is \(1^{st}\times2nd = 3^{rd}; 2^{nd}\times3rd= 4^{th}; 3^{rd}\times4th = 5^{th}\)
But, \(4^{th}\times5th = 50\times500 = 25000\neq5000=6^{th}\)UnattemptedPattern is \(1^{st}\times2nd = 3^{rd}; 2^{nd}\times3rd= 4^{th}; 3^{rd}\times4th = 5^{th}\)
But, \(4^{th}\times5th = 50\times500 = 25000\neq5000=6^{th}\)  Question 10 of 10
10. Question
1 points41, 43, 47, 53, 61, 71, 73, 81
Find the odd man out.
CorrectEach of the numbers except 81, is a prime number.
IncorrectEach of the numbers except 81, is a prime number.
UnattemptedEach of the numbers except 81, is a prime number.