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Quiz Description :
Name : Pipe and Cistern practice test
Subject : Aptitude
Topic : Pipe and Cistern
Questions: 15 mcq
Time Allowed : 20 Min
Important for : School, College and competitions
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 Question 1 of 15
1. Question
1 pointsTwo pipes A and B can fill a tank in 20 and 30 minutes respectively. I f both the pipes are used together, then how long will it take to fill the tank?
CorrectExplanations: Part filled by A in1 min. = 1/20; Part filled by B in min. = 1/30.
Part filled by (A+B) in 1 min. = (1/20+1/30) = 1/12.
Both the pipes can fill the tank in 12 minutes.
IncorrectExplanations: Part filled by A in1 min. = 1/20; Part filled by B in min. = 1/30.
Part filled by (A+B) in 1 min. = (1/20+1/30) = 1/12.
Both the pipes can fill the tank in 12 minutes.
UnattemptedExplanations: Part filled by A in1 min. = 1/20; Part filled by B in min. = 1/30.
Part filled by (A+B) in 1 min. = (1/20+1/30) = 1/12.
Both the pipes can fill the tank in 12 minutes.
 Question 2 of 15
2. Question
1 pointsA cistern can be filled by filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
CorrectExplanations: Net part filled in 1 hour = (1/41/9) = 5/36.
The cistern will be filled in 36/5 hrs i.e., 7.2 hrs.
IncorrectExplanations: Net part filled in 1 hour = (1/41/9) = 5/36.
The cistern will be filled in 36/5 hrs i.e., 7.2 hrs.
UnattemptedExplanations: Net part filled in 1 hour = (1/41/9) = 5/36.
The cistern will be filled in 36/5 hrs i.e., 7.2 hrs.
 Question 3 of 15
3. Question
1 pointsA tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
CorrectExplanations: Time taken by one tap to fill half the tank = 3 hrs.
Part filled by the four taps in 1 hour = (4/6) =2/3.
Remaining part = (11/2) = ½.
2/3: ½: 1: x
Or x = (1/2 × 1 × 3/2) = ¾ hrs i.e., 45 mins.
SO, total time taken = 3 hrs 45 min.
IncorrectExplanations: Time taken by one tap to fill half the tank = 3 hrs.
Part filled by the four taps in 1 hour = (4/6) =2/3.
Remaining part = (11/2) = ½.
2/3: ½: 1: x
Or x = (1/2 × 1 × 3/2) = ¾ hrs i.e., 45 mins.
SO, total time taken = 3 hrs 45 min.
UnattemptedExplanations: Time taken by one tap to fill half the tank = 3 hrs.
Part filled by the four taps in 1 hour = (4/6) =2/3.
Remaining part = (11/2) = ½.
2/3: ½: 1: x
Or x = (1/2 × 1 × 3/2) = ¾ hrs i.e., 45 mins.
SO, total time taken = 3 hrs 45 min.
 Question 4 of 15
4. Question
1 pointsA water tank is two fifth full. Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes. If both the pipes are open, how long will it take to empty or fill the tank completely?
CorrectExplanations:
Clearly, pipe B is faster than pipe A and so, the tank will be emptied.
Part to be emptied 2/5.
Part emptied by (A+B) in minute = (1/61/10) = 1/15.
1/15: 2/5:: 1: x or x = (2/5 × 1 × 15) = 6 min.
So, the tank will be emptied in 6 min.
IncorrectExplanations:
Clearly, pipe B is faster than pipe A and so, the tank will be emptied.
Part to be emptied 2/5.
Part emptied by (A+B) in minute = (1/61/10) = 1/15.
1/15: 2/5:: 1: x or x = (2/5 × 1 × 15) = 6 min.
So, the tank will be emptied in 6 min.
UnattemptedExplanations:
Clearly, pipe B is faster than pipe A and so, the tank will be emptied.
Part to be emptied 2/5.
Part emptied by (A+B) in minute = (1/61/10) = 1/15.
1/15: 2/5:: 1: x or x = (2/5 × 1 × 15) = 6 min.
So, the tank will be emptied in 6 min.
 Question 5 of 15
5. Question
1 pointsPipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will take be filled?
CorrectExplanations: Part filled by (A+B+C) in 1 hour = (1/5+1/10+1/30) = 1/3.
All the three pipes together will fill the tank in 3 hours.IncorrectExplanations: Part filled by (A+B+C) in 1 hour = (1/5+1/10+1/30) = 1/3.
All the three pipes together will fill the tank in 3 hours.UnattemptedExplanations: Part filled by (A+B+C) in 1 hour = (1/5+1/10+1/30) = 1/3.
All the three pipes together will fill the tank in 3 hours.  Question 6 of 15
6. Question
1 pointsPipe A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the will be filled in:
CorrectExplanations: Net part filled in 1 hour = (1/5+1/61/12) = 17/60.
The tank will be full in 60/17 hrs i.e. , 60/17 hrs.
IncorrectExplanations: Net part filled in 1 hour = (1/5+1/61/12) = 17/60.
The tank will be full in 60/17 hrs i.e. , 60/17 hrs.
UnattemptedExplanations: Net part filled in 1 hour = (1/5+1/61/12) = 17/60.
The tank will be full in 60/17 hrs i.e. , 60/17 hrs.
 Question 7 of 15
7. Question
1 pointsThree pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes and 10 minutes respectively. When the tank is empty, all three pipes are opened. A, B and C discharge chemical solutions P, Q and R respectively. What is the proportion of solution R in the liquid in the tank after 3 minutes?
CorrectExplanations: Part filled by (A+B+C) in 3 minutes = 3(1/30+1/20+1/10) = (3 × 11/60) = 11/20.
Part filled by C in 3 minutes = 3/10.
Required ratio = (3/10 × 20/11) = 6/11.
IncorrectExplanations: Part filled by (A+B+C) in 3 minutes = 3(1/30+1/20+1/10) = (3 × 11/60) = 11/20.
Part filled by C in 3 minutes = 3/10.
Required ratio = (3/10 × 20/11) = 6/11.
UnattemptedExplanations: Part filled by (A+B+C) in 3 minutes = 3(1/30+1/20+1/10) = (3 × 11/60) = 11/20.
Part filled by C in 3 minutes = 3/10.
Required ratio = (3/10 × 20/11) = 6/11.
 Question 8 of 15
8. Question
1 pointsTwo pipes A and B can separately fill a cistern in 60 minutes and 75 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 minutes. In how much time, the third pipe alone can empty the cistern?
CorrectExplanations: Weak done by the third pipe in 1 min.
= 1/50(1/60+1/75) = (1/503/100) = 1/100.
The third pipe along can empty the cistern in 100 min.
IncorrectExplanations: Weak done by the third pipe in 1 min.
= 1/50(1/60+1/75) = (1/503/100) = 1/100.
The third pipe along can empty the cistern in 100 min.
UnattemptedExplanations: Weak done by the third pipe in 1 min.
= 1/50(1/60+1/75) = (1/503/100) = 1/100.
The third pipe along can empty the cistern in 100 min.
 Question 9 of 15
9. Question
1 pointsA pump can fill a tank with water in 2 hours. Because of a leak, it took 7/3 hours to fill the tank. The leak can drain all the water of the tank in:
CorrectExplanations: Work done by the leak in 1 hour = (1/23/7) = 1/14.
Leak will empty the tank in 14 hrs.
IncorrectExplanations: Work done by the leak in 1 hour = (1/23/7) = 1/14.
Leak will empty the tank in 14 hrs.
UnattemptedExplanations: Work done by the leak in 1 hour = (1/23/7) = 1/14.
Leak will empty the tank in 14 hrs.
 Question 10 of 15
10. Question
1 pointsTwo taps A and B can fill a tank in 5 hours and 20 hours respectively. If both the taps are open then due to a leakage, it took 30 minutes more to fill the tank. If the tank is full, how long will it take for the leakage alone to empty the tank?
CorrectExplanations: Part filled by (A+B) in 1 hour = (1/5+1/20) =1/4.
So, A and B together can fill the tank in 04 hrs.
Work done by the leak in 1 hour = [1/42/9] = 1/36
So Leak will empty the tank in 36 hours.IncorrectExplanations: Part filled by (A+B) in 1 hour = (1/5+1/20) =1/4.
So, A and B together can fill the tank in 04 hrs.
Work done by the leak in 1 hour = [1/42/9] = 1/36
So Leak will empty the tank in 36 hours.UnattemptedExplanations: Part filled by (A+B) in 1 hour = (1/5+1/20) =1/4.
So, A and B together can fill the tank in 04 hrs.
Work done by the leak in 1 hour = [1/42/9] = 1/36
So Leak will empty the tank in 36 hours.  Question 11 of 15
11. Question
1 pointsTwo pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
CorrectExplanations: Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x+6) hours.
1/x+1/(x+6) =1/4
x+6+x/x(x+6) = ¼
x^22x24 = 0
(x6) (x+4) = 0
x = 6.IncorrectExplanations: Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x+6) hours.
1/x+1/(x+6) =1/4
x+6+x/x(x+6) = ¼
x^22x24 = 0
(x6) (x+4) = 0
x = 6.UnattemptedExplanations: Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x+6) hours.
1/x+1/(x+6) =1/4
x+6+x/x(x+6) = ¼
x^22x24 = 0
(x6) (x+4) = 0
x = 6.  Question 12 of 15
12. Question
1 pointsOne pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe along will be able to fill the tank in :
CorrectExplanations: Let the slower pipe along fill the tank in x minutes.
Then, faster pipe will fill it in x/3 minutes.
1/x+3/x = 1/36 <==> 4/x = 1/36 <==> x= 144 min.
IncorrectExplanations: Let the slower pipe along fill the tank in x minutes.
Then, faster pipe will fill it in x/3 minutes.
1/x+3/x = 1/36 <==> 4/x = 1/36 <==> x= 144 min.
UnattemptedExplanations: Let the slower pipe along fill the tank in x minutes.
Then, faster pipe will fill it in x/3 minutes.
1/x+3/x = 1/36 <==> 4/x = 1/36 <==> x= 144 min.
 Question 13 of 15
13. Question
1 pointsA tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A along take to fill the tank?
CorrectExplanations: Suppose pipe A along takes x hours to fill the tank.
Then, faster pipe B and C will take x/2 and x/4 hours respectively to fill the tank.
[1/x]+[2/x]+[4/x] = 1/5
7/x = 1/5
x=35 hrs.IncorrectExplanations: Suppose pipe A along takes x hours to fill the tank.
Then, faster pipe B and C will take x/2 and x/4 hours respectively to fill the tank.
[1/x]+[2/x]+[4/x] = 1/5
7/x = 1/5
x=35 hrs.UnattemptedExplanations: Suppose pipe A along takes x hours to fill the tank.
Then, faster pipe B and C will take x/2 and x/4 hours respectively to fill the tank.
[1/x]+[2/x]+[4/x] = 1/5
7/x = 1/5
x=35 hrs.  Question 14 of 15
14. Question
1 pointsA tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe along. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is:
CorrectExplanations: Suppose, first pipe along takes x hours to fill the tank. Then, second and third pipes will take (x5) and (x9) hours respectively to fill the tank.
[1/x]+[1/(x5)] = [1/(x9)]
[ (x5)+x]/[x(x5)] = 1/(x9)
(2x5) (x9) = x (x5)
x^218x+45 = 0
(x15) (x3) = 0
x = 15.IncorrectExplanations: Suppose, first pipe along takes x hours to fill the tank. Then, second and third pipes will take (x5) and (x9) hours respectively to fill the tank.
[1/x]+[1/(x5)] = [1/(x9)]
[ (x5)+x]/[x(x5)] = 1/(x9)
(2x5) (x9) = x (x5)
x^218x+45 = 0
(x15) (x3) = 0
x = 15.UnattemptedExplanations: Suppose, first pipe along takes x hours to fill the tank. Then, second and third pipes will take (x5) and (x9) hours respectively to fill the tank.
[1/x]+[1/(x5)] = [1/(x9)]
[ (x5)+x]/[x(x5)] = 1/(x9)
(2x5) (x9) = x (x5)
x^218x+45 = 0
(x15) (x3) = 0
x = 15.  Question 15 of 15
15. Question
1 points12 buckets of water fill a tank when the capacity of each tank is 13.5 litters. How many buckets will be needed to fill the tank in the same time, if the capacity of each bucket is 9 liters?
CorrectExplanations: Capacity of the tank = (12 × 13.5) litres = 162 litres.
Capacity of each bucket = 9 litres.
Number of buckets needed = (162/9) = 18.
IncorrectExplanations: Capacity of the tank = (12 × 13.5) litres = 162 litres.
Capacity of each bucket = 9 litres.
Number of buckets needed = (162/9) = 18.
UnattemptedExplanations: Capacity of the tank = (12 × 13.5) litres = 162 litres.
Capacity of each bucket = 9 litres.
Number of buckets needed = (162/9) = 18.