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Test Overview
Name : Simplification Objective Aptitude Practice Test
Subject : Aptitude / Maths
Topic : Simplification
Time : 15 Minutes
Explanation : Available
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 Question 1 of 15
1. Question
1 pointsN no. Of persons decided to raise Rs. 3 lakhs by equal contributions from each. And they contribute Rs. 50 extra, the contribution would have been Rs. 3.25 lakhs. How many persons are they?
CorrectExplanation – N×50 = (325000300000) = 25000
So, N= 25000/50
N= 500
IncorrectExplanation – N×50 = (325000300000) = 25000
So, N= 25000/50
N= 500
UnattemptedExplanation – N×50 = (325000300000) = 25000
So, N= 25000/50
N= 500
 Question 2 of 15
2. Question
1 pointsIn an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 130 marks then the no. Of questions he correctly answered is
CorrectExplanation – Let the no. Of correct answer be x
So, no. Of incorrect answer is (60x)
Then, 4x(60x) = 130
5x = 190
x = 38
IncorrectExplanation – Let the no. Of correct answer be x
So, no. Of incorrect answer is (60x)
Then, 4x(60x) = 130
5x = 190
x = 38
UnattemptedExplanation – Let the no. Of correct answer be x
So, no. Of incorrect answer is (60x)
Then, 4x(60x) = 130
5x = 190
x = 38
 Question 3 of 15
3. Question
1 pointsIn a group of Cows and hens, the no. Of legs are 24 more than twice the no. Of heads. What is the no. Of cow in the group?
CorrectExplanation – Let the no. Of cows be x and the no. Of hens be y
then, 4x + 2y = 2(x+y) + 24
4x+2y = 2x + 2y + 24
4x+2y – 2x2y = 24
2x= 24
x = 12
IncorrectExplanation – Let the no. Of cows be x and the no. Of hens be y
then, 4x + 2y = 2(x+y) + 24
4x+2y = 2x + 2y + 24
4x+2y – 2x2y = 24
2x= 24
x = 12
UnattemptedExplanation – Let the no. Of cows be x and the no. Of hens be y
then, 4x + 2y = 2(x+y) + 24
4x+2y = 2x + 2y + 24
4x+2y – 2x2y = 24
2x= 24
x = 12
 Question 4 of 15
4. Question
1 pointsAn employer pays Rs. 20 for each day a worker works, and forfeit Rs. 3 for each day he is idle. At the end of 60 days, a worker gets Rs. 280. For how many days was the worker out of work?
CorrectExplanation – suppose the idle days be x then, he works for (60x) days
20(60x)3x = 280
= 1200 – 23x = 280
= 23x = 920
x = 40
IncorrectExplanation – suppose the idle days be x then, he works for (60x) days
20(60x)3x = 280
= 1200 – 23x = 280
= 23x = 920
x = 40
UnattemptedExplanation – suppose the idle days be x then, he works for (60x) days
20(60x)3x = 280
= 1200 – 23x = 280
= 23x = 920
x = 40
 Question 5 of 15
5. Question
1 pointsVillage x has a population of 68000, which is decreasing at a rate of 1200 per year. Village y has a population of 42000, which is increasing at a rate of 800 per year. In how many years will the population of 2 villages be equal?
CorrectExplanation – Let the population of villages x and y equal be n years, then,
680001200n = 42000+800n
2000n = 26000
n = 26000/2000
n = 13
IncorrectExplanation – Let the population of villages x and y equal be n years, then,
680001200n = 42000+800n
2000n = 26000
n = 26000/2000
n = 13
UnattemptedExplanation – Let the population of villages x and y equal be n years, then,
680001200n = 42000+800n
2000n = 26000
n = 26000/2000
n = 13
 Question 6 of 15
6. Question
1 pointsA man has 480 in the denominations of one rupee notes, five rupees notes and 10 rupees notes. The no.of notes of each denomination is equal. What is the total no. Of notes he has?
CorrectExplanation – Let no. Of notes of each denomination be x, then
x+5x+10x = 480
16x = 480
x = 30, he has 3 type of notes
hence, the total no. Of notes 3x = 90.
IncorrectExplanation – Let no. Of notes of each denomination be x, then
x+5x+10x = 480
16x = 480
x = 30, he has 3 type of notes
hence, the total no. Of notes 3x = 90.
UnattemptedExplanation – Let no. Of notes of each denomination be x, then
x+5x+10x = 480
16x = 480
x = 30, he has 3 type of notes
hence, the total no. Of notes 3x = 90.
 Question 7 of 15
7. Question
1 pointsThe price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 table together is 4000 Rs. The total price of 12 chairs and 3 tables is
CorrectExplanation – Let the cost of a chair and a table be x and y respectively, then,
10x = 4y or y = (5/2)x
15x + 2y = 4000
15x + 2(5/2)x = 4000
20x = 4000
x = 200
So, y = (5/2) × 200 = 500
Hence, the cost of 12 chairs and 3 tables = 12x+3y
= 2400 + 1500
= 3900 Rs.
IncorrectExplanation – Let the cost of a chair and a table be x and y respectively, then,
10x = 4y or y = (5/2)x
15x + 2y = 4000
15x + 2(5/2)x = 4000
20x = 4000
x = 200
So, y = (5/2) × 200 = 500
Hence, the cost of 12 chairs and 3 tables = 12x+3y
= 2400 + 1500
= 3900 Rs.
UnattemptedExplanation – Let the cost of a chair and a table be x and y respectively, then,
10x = 4y or y = (5/2)x
15x + 2y = 4000
15x + 2(5/2)x = 4000
20x = 4000
x = 200
So, y = (5/2) × 200 = 500
Hence, the cost of 12 chairs and 3 tables = 12x+3y
= 2400 + 1500
= 3900 Rs.
 Question 8 of 15
8. Question
1 pointsWhat is the sum of no. of all 2 digit numbers that gives a remainder 3 when they are divided by 7?
CorrectExplanation – The numbers are :
10, 17, 24,…..94.
These no. Are in AP series with first term,
a = 10 , n= 13, L = 94 and common difference (d) = 7
Sum, {n*(a+L)/2}
13*52 = 676
IncorrectExplanation – The numbers are :
10, 17, 24,…..94.
These no. Are in AP series with first term,
a = 10 , n= 13, L = 94 and common difference (d) = 7
Sum, {n*(a+L)/2}
13*52 = 676
UnattemptedExplanation – The numbers are :
10, 17, 24,…..94.
These no. Are in AP series with first term,
a = 10 , n= 13, L = 94 and common difference (d) = 7
Sum, {n*(a+L)/2}
13*52 = 676
 Question 9 of 15
9. Question
1 pointsIf ab = 3 and a square+b square= 29, find the value of ab
CorrectExplanation – 2ab = (a2+b2) – (a+b)2
299 = 20
ab = 10
IncorrectExplanation – 2ab = (a2+b2) – (a+b)2
299 = 20
ab = 10
UnattemptedExplanation – 2ab = (a2+b2) – (a+b)2
299 = 20
ab = 10
 Question 10 of 15
10. Question
1 pointsA sum of Rs. 1360 has been divided among P, Q and R such that, P gets 2/3 of what Q gets and Q gets 1/4 of what R gets, Q’s share is?
CorrectExplanation – Lets R share be x
then, Q share is x/4 and P share = 2/3 × x/4 = x/6
x/6 + x/4 + x = 1360
17x/12 = 1360
x = 960
hence, Q’s share is 960/4 = Rs. 240
IncorrectExplanation – Lets R share be x
then, Q share is x/4 and P share = 2/3 × x/4 = x/6
x/6 + x/4 + x = 1360
17x/12 = 1360
x = 960
hence, Q’s share is 960/4 = Rs. 240
UnattemptedExplanation – Lets R share be x
then, Q share is x/4 and P share = 2/3 × x/4 = x/6
x/6 + x/4 + x = 1360
17x/12 = 1360
x = 960
hence, Q’s share is 960/4 = Rs. 240
 Question 11 of 15
11. Question
1 pointsTo fill a tank 25 buckets if water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to 2/5th of its present
CorrectExplanation – Let the capacity of 1 bucket be x then, the capacity of tank is 25x and new capacity of bucket is 2/5x.
So, required no. Of buckets = 25x/2x/5
= 125/2
= 62.5
IncorrectExplanation – Let the capacity of 1 bucket be x then, the capacity of tank is 25x and new capacity of bucket is 2/5x.
So, required no. Of buckets = 25x/2x/5
= 125/2
= 62.5
UnattemptedExplanation – Let the capacity of 1 bucket be x then, the capacity of tank is 25x and new capacity of bucket is 2/5x.
So, required no. Of buckets = 25x/2x/5
= 125/2
= 62.5
 Question 12 of 15
12. Question
1 pointsA man has some buffaloes and ducks. If the no. Of heads be 48 and the no. Of feet equals to 140. Then the no. Of ducks wil be
CorrectExplanation – let the no. Of ducks be x and the no. Of buffaloes be y then,
x+y = 48…..1
2x+4y = 140 => x+2y = 70…..2
By 1 and 2 we will get..
x = 26 and y = 22.
IncorrectExplanation – let the no. Of ducks be x and the no. Of buffaloes be y then,
x+y = 48…..1
2x+4y = 140 => x+2y = 70…..2
By 1 and 2 we will get..
x = 26 and y = 22.
UnattemptedExplanation – let the no. Of ducks be x and the no. Of buffaloes be y then,
x+y = 48…..1
2x+4y = 140 => x+2y = 70…..2
By 1 and 2 we will get..
x = 26 and y = 22.
 Question 13 of 15
13. Question
1 pointsFree notebooks distributed equally among school children of a class. The no. Of notebooks each child got was 1/8th of the no. Of children. Had the no. Of children be half, each child would have got 16 notebooks. Total how many notebooks were distributed?
CorrectExplanation – Let total no. Of children be x then,
x × 1/8x = x/2 × 16
x = 64
No..of notebooks = (1/8×64×64)
= 512
IncorrectExplanation – Let total no. Of children be x then,
x × 1/8x = x/2 × 16
x = 64
No..of notebooks = (1/8×64×64)
= 512
UnattemptedExplanation – Let total no. Of children be x then,
x × 1/8x = x/2 × 16
x = 64
No..of notebooks = (1/8×64×64)
= 512
 Question 14 of 15
14. Question
1 points8 people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and other share equally the entire cost of car, then the share of each of the remaining persons increased by
CorrectExplanation – original share of 1 person is 1/8
New share of 1 person is 1/7
Increased share = 1/71/8 = 1/56
hence, 1/56/1/8 = 1/56 × 8/1
= 1/7
IncorrectExplanation – original share of 1 person is 1/8
New share of 1 person is 1/7
Increased share = 1/71/8 = 1/56
hence, 1/56/1/8 = 1/56 × 8/1
= 1/7
UnattemptedExplanation – original share of 1 person is 1/8
New share of 1 person is 1/7
Increased share = 1/71/8 = 1/56
hence, 1/56/1/8 = 1/56 × 8/1
= 1/7
 Question 15 of 15
15. Question
1 pointsSix times the sum of the digit of a 2 digits no. Is one less than the no. And 8 more than the no. Obtained by reversing the digits of the no. Find the product of the number
CorrectExplanation – Let the no. Be xy then,
6 (x+y)+1 = 10x+y……1
6 (x+y) = 8 = 10y + x……2
from 1 and 2 we will get,
x = 4
y = 3 then,
xy = 12.
IncorrectExplanation – Let the no. Be xy then,
6 (x+y)+1 = 10x+y……1
6 (x+y) = 8 = 10y + x……2
from 1 and 2 we will get,
x = 4
y = 3 then,
xy = 12.
UnattemptedExplanation – Let the no. Be xy then,
6 (x+y)+1 = 10x+y……1
6 (x+y) = 8 = 10y + x……2
from 1 and 2 we will get,
x = 4
y = 3 then,
xy = 12.