Aptitude
Time and Distance

Time and Distance mcq quiz – Level 1

You can attempt previous Data Sufficiency Objective Question answer test or next Time and Distance mcq Quiz – Level 2

Yuvayana Admin

Jun 13, 2016

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Last Updated on Mar 14, 2023

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Quiz Description :

Name: Time and Distance mcq quiz – Level 1

Subject: Quantitative Aptitude

Topic: Speed Time and Distance

Questions: 12 mcq type

Time Allowed: 20 minutes

Language: English

Difficulty Level: 1 out of 10.

Important for: SSC CHSL, Amry, BSF, CRPF, Railways, Bank Clerk and 12th level competitions, 8th, 9th, 10th class school students.

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Question 1 of 12

1. Question
1 points
A man runs at the rate of 45 km an hour. What is its speed in meters per second?
- 12.0 meters per second
- 12. 5 meters per second
- 13.5 meters per second
- 18.9 meters per second
Correct

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 45 km per hour     = 45 × [5 / 18] meters per second
i.e. = 12.5 meters per second

Incorrect

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 45 km per hour     = 45 × [5 / 18] meters per second
i.e. = 12.5 meters per second

Unattempted

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 45 km per hour     = 45 × [5 / 18] meters per second
i.e. = 12.5 meters per second
Question 2 of 12

2. Question
1 points
In a marathon a person runs at the rate of 18 km an hour. What is its speed in meters per second?
- 6 meters per second
- 8 meters per second
- 5 meters per second
- 10 meters per second
Correct

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 18 km per hour     = 18 × [5 / 18] meters per second
i.e. = 5 meters per second

Incorrect

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 18 km per hour     = 18 × [5 / 18] meters per second
i.e. = 5 meters per second

Unattempted

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 18 km per hour     = 18 × [5 / 18] meters per second
i.e. = 5 meters per second
Question 3 of 12

3. Question
1 points
How many meter per second does a man walk who passes thorough a street 15 kilometre long in one hours.
- 4.1667 meter per second
- 4.896 meter per second
- 5.1289 meter per second
- 3.895 meter per second
Correct

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 15 km per hour     = 15 × [5 / 18] meters per second
i.e. = 4.1667 meters per second

Incorrect

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 15 km per hour     = 15 × [5 / 18] meters per second
i.e. = 4.1667 meters per second

Unattempted

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 15 km per hour     = 15 × [5 / 18] meters per second
i.e. = 4.1667 meters per second
Question 4 of 12

4. Question
1 points
A bike racer ride his bike at the rate of 124 km in an hour. What is its speed in meters per second?
- 34.44 meter per second
- 50.00 meter per second
- 36.78 meter per second
- 34.96 meter per second
Correct

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 124 km per hour = 124 × [5 / 18] meters per second
i.e. = 34.44 meters per second

Incorrect

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 124 km per hour = 124 × [5 / 18] meters per second
i.e. = 34.44 meters per second

Unattempted

A km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 124 km per hour = 124 × [5 / 18] meters per second
i.e. = 34.44 meters per second
Question 5 of 12

5. Question
1 points
A train runs at speed of 28 meter per second. What is its speed in kilometer per hours?
- 101 kilometers per hour
- 100.8 kilometers per hour
- 100.8 kilometers per second
- 110 kilometers per hour
Correct

A meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 28 meters per second= 28 × [18 / 5] kilometer per hour
i.e. = 100.8 kilometer per second

Incorrect

A meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 28 meters per second= 28 × [18 / 5] kilometer per hour
i.e. = 100.8 kilometer per second

Unattempted

A meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 28 meters per second= 28 × [18 / 5] kilometer per hour
i.e. = 100.8 kilometer per second
Question 6 of 12

6. Question
1 points
In a bike riding race a bike rider ride his bike at the rate of 22 meter per second. What is its speed in kilometers per hour?
- 79.2 meters per hour
- 82.89 kilometers per hour
- 79.2 kilometers per hour
- 792 kilometers per hour
Correct

A meters per second= A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 22 meters per second = 22 × [18 / 5] kilometer per hour
i.e. = 79.2 kilometer per second

Incorrect

A meters per second= A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 22 meters per second = 22 × [18 / 5] kilometer per hour
i.e. = 79.2 kilometer per second

Unattempted

A meters per second= A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 22 meters per second = 22 × [18 / 5] kilometer per hour
i.e. = 79.2 kilometer per second
Question 7 of 12

7. Question
1 points
How many kilometers in an hour does a man walk who passes thorough a street 3 meter long in one second.
- 12.8 meters per hour
- 10.8 Km/s
- 108 kilometers per hour
- 10.8 kilometers per hour
Correct

A meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 3 meters per second = 3 × [18 / 5] kilometer per hour
i.e. = 10.8 kilometer per second

Incorrect

A meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 3 meters per second = 3 × [18 / 5] kilometer per hour
i.e. = 10.8 kilometer per second

Unattempted

A meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 3 meters per second = 3 × [18 / 5] kilometer per hour
i.e. = 10.8 kilometer per second
Question 8 of 12

8. Question
1 points
A man covers a certain distance by car driving at 70 km/hrs and he returns back to the starting point riding on a scooter at 55 km/hrs. Find his average speed for the whole journey.
- 69.6 Km/hrs
- 61.6 km/hrs.
- 6.16 km/hrs
- 61.6 m/hrs
Correct

To calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs = 61.6 km/hrs

Incorrect

To calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs = 61.6 km/hrs

Unattempted

To calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs = 61.6 km/hrs
Question 9 of 12

9. Question
1 points
A car driver covers a certain distance by his car driving at 80 km/hrs and he returns back to the initial point riding another car at the speed of 68 km/hrs. Find his average speed for the whole journey.
- 80.5 kilometers per hour
- 75.51 km/hrs
- 73.51 km/hrs
- None of these
Correct

To calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = 2 × [80 × 68] / [80 + 68] km/hrs
= 73.51 km/hrs

Incorrect

To calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = 2 × [80 × 68] / [80 + 68] km/hrs
= 73.51 km/hrs

Unattempted

To calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = 2 × [80 × 68] / [80 + 68] km/hrs
= 73.51 km/hrs
Question 10 of 12

10. Question
1 points
A man covers a certain distance by car driving at 70 km/hrs and he returns back to the starting point riding on a scooter at 55 km/hrs. Find his average speed for the whole journey in meter per second.
- 18.19 km/hrs
- 17.11 meter per second
- 18.11 meter per second
- 19.89 meter per second
Correct

To calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs
= 61.6 km/hrs
= 61. 6 × [5 / 18] meter per second
= 17.11 meter per second

Incorrect

To calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs
= 61.6 km/hrs
= 61. 6 × [5 / 18] meter per second
= 17.11 meter per second

Unattempted

To calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs
= 61.6 km/hrs
= 61. 6 × [5 / 18] meter per second
= 17.11 meter per second
Question 11 of 12

11. Question
1 points
A boy goes to school at a speed of 3 km.hr and returns to the village at a speed of 2 km/hr. If he takes 5 hrs in all, what is the distance between the village and the school?
- 10 Kilometer
- 6 Kilometer
- 9 Kilometer
- 15 Kilometer
Correct

Required distance = [(Product of Two speeds)/(Addition of two speed)]× (Total time taken)
= [(3 × 2)/ (3 + 2)] × 5
= 6 Kilometer

Incorrect

Required distance = [(Product of Two speeds)/(Addition of two speed)]× (Total time taken)
= [(3 × 2)/ (3 + 2)] × 5
= 6 Kilometer

Unattempted

Required distance = [(Product of Two speeds)/(Addition of two speed)]× (Total time taken)
= [(3 × 2)/ (3 + 2)] × 5
= 6 Kilometer
Question 12 of 12

12. Question
1 points
A motor car does a journey in 10 hours, the first half at 21 kilometer/hrs. and the second half at 24 kilometer/hrs. What is the total distance of the journey?
- 224 Kilometer
- 250 Kilometer
- 220 Kilometer
- 230 Kilometer
Correct

The Required distance = [(Product of Two speeds)/(Addition of two speed)] × (Total time taken) × 2
= [(21 × 24)/ (21 + 24)] × 10 × 2
= 224 Kilometer

Incorrect

The Required distance = [(Product of Two speeds)/(Addition of two speed)] × (Total time taken) × 2
= [(21 × 24)/ (21 + 24)] × 10 × 2
= 224 Kilometer

Unattempted

The Required distance = [(Product of Two speeds)/(Addition of two speed)] × (Total time taken) × 2
= [(21 × 24)/ (21 + 24)] × 10 × 2
= 224 Kilometer