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Quiz Description :
Name: Time and Distance mcq quiz – Level 1
Subject: Quantitative Aptitude
Topic: Speed Time and Distance
Questions: 12 mcq type
Time Allowed: 20 minutes
Language: English
Difficulty Level: 1 out of 10.
Important for: SSC CHSL, Amry, BSF, CRPF, Railways, Bank Clerk and 12th level competitions, 8th, 9th, 10th class school students.
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 Question 1 of 12
1. Question
1 pointsA man runs at the rate of 45 km an hour. What is its speed in meters per second?
CorrectA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 45 km per hour = 45 × [5 / 18] meters per second
i.e. = 12.5 meters per secondIncorrectA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 45 km per hour = 45 × [5 / 18] meters per second
i.e. = 12.5 meters per secondUnattemptedA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 45 km per hour = 45 × [5 / 18] meters per second
i.e. = 12.5 meters per second  Question 2 of 12
2. Question
1 pointsIn a marathon a person runs at the rate of 18 km an hour. What is its speed in meters per second?
CorrectA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 18 km per hour = 18 × [5 / 18] meters per second
i.e. = 5 meters per secondIncorrectA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 18 km per hour = 18 × [5 / 18] meters per second
i.e. = 5 meters per secondUnattemptedA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 18 km per hour = 18 × [5 / 18] meters per second
i.e. = 5 meters per second  Question 3 of 12
3. Question
1 pointsHow many meter per second does a man walk who passes thorough a street 15 kilometre long in one hours.
CorrectA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 15 km per hour = 15 × [5 / 18] meters per second
i.e. = 4.1667 meters per secondIncorrectA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 15 km per hour = 15 × [5 / 18] meters per second
i.e. = 4.1667 meters per secondUnattemptedA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 15 km per hour = 15 × [5 / 18] meters per second
i.e. = 4.1667 meters per second  Question 4 of 12
4. Question
1 pointsA bike racer ride his bike at the rate of 124 km in an hour. What is its speed in meters per second?
CorrectA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 124 km per hour = 124 × [5 / 18] meters per second
i.e. = 34.44 meters per secondIncorrectA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 124 km per hour = 124 × [5 / 18] meters per second
i.e. = 34.44 meters per secondUnattemptedA km per hour = A × [1000 / 60 × 60] = A × [5 / 18] meters per second
Thus, 124 km per hour = 124 × [5 / 18] meters per second
i.e. = 34.44 meters per second  Question 5 of 12
5. Question
1 pointsA train runs at speed of 28 meter per second. What is its speed in kilometer per hours?
CorrectA meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 28 meters per second= 28 × [18 / 5] kilometer per hour
i.e. = 100.8 kilometer per secondIncorrectA meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 28 meters per second= 28 × [18 / 5] kilometer per hour
i.e. = 100.8 kilometer per secondUnattemptedA meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 28 meters per second= 28 × [18 / 5] kilometer per hour
i.e. = 100.8 kilometer per second  Question 6 of 12
6. Question
1 pointsIn a bike riding race a bike rider ride his bike at the rate of 22 meter per second. What is its speed in kilometers per hour?
CorrectA meters per second= A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 22 meters per second = 22 × [18 / 5] kilometer per hour
i.e. = 79.2 kilometer per secondIncorrectA meters per second= A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 22 meters per second = 22 × [18 / 5] kilometer per hour
i.e. = 79.2 kilometer per secondUnattemptedA meters per second= A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 22 meters per second = 22 × [18 / 5] kilometer per hour
i.e. = 79.2 kilometer per second  Question 7 of 12
7. Question
1 pointsHow many kilometers in an hour does a man walk who passes thorough a street 3 meter long in one second.
CorrectA meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 3 meters per second = 3 × [18 / 5] kilometer per hour
i.e. = 10.8 kilometer per secondIncorrectA meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 3 meters per second = 3 × [18 / 5] kilometer per hour
i.e. = 10.8 kilometer per secondUnattemptedA meters per second = A × [60 × 60 / 1000] = A × [18 / 5] kilometers per hour
Thus, 3 meters per second = 3 × [18 / 5] kilometer per hour
i.e. = 10.8 kilometer per second  Question 8 of 12
8. Question
1 pointsA man covers a certain distance by car driving at 70 km/hrs and he returns back to the starting point riding on a scooter at 55 km/hrs. Find his average speed for the whole journey.
CorrectTo calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs = 61.6 km/hrsIncorrectTo calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs = 61.6 km/hrsUnattemptedTo calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs = 61.6 km/hrs  Question 9 of 12
9. Question
1 pointsA car driver covers a certain distance by his car driving at 80 km/hrs and he returns back to the initial point riding another car at the speed of 68 km/hrs. Find his average speed for the whole journey.
CorrectTo calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = 2 × [80 × 68] / [80 + 68] km/hrs
= 73.51 km/hrsIncorrectTo calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = 2 × [80 × 68] / [80 + 68] km/hrs
= 73.51 km/hrsUnattemptedTo calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = 2 × [80 × 68] / [80 + 68] km/hrs
= 73.51 km/hrs  Question 10 of 12
10. Question
1 pointsA man covers a certain distance by car driving at 70 km/hrs and he returns back to the starting point riding on a scooter at 55 km/hrs. Find his average speed for the whole journey in meter per second.
CorrectTo calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs
= 61.6 km/hrs
= 61. 6 × [5 / 18] meter per second
= 17.11 meter per secondIncorrectTo calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs
= 61.6 km/hrs
= 61. 6 × [5 / 18] meter per second
= 17.11 meter per secondUnattemptedTo calculate the average speed we use = 2 × [Product of the speeds] / [Summation of the speeds]
The average speed of the man in the whole journey is = [2 × 70 × 55] / [70 + 55] km/hrs
= 61.6 km/hrs
= 61. 6 × [5 / 18] meter per second
= 17.11 meter per second  Question 11 of 12
11. Question
1 pointsA boy goes to school at a speed of 3 km.hr and returns to the village at a speed of 2 km/hr. If he takes 5 hrs in all, what is the distance between the village and the school?
CorrectRequired distance = [(Product of Two speeds)/(Addition of two speed)]× (Total time taken)
= [(3 × 2)/ (3 + 2)] × 5
= 6 KilometerIncorrectRequired distance = [(Product of Two speeds)/(Addition of two speed)]× (Total time taken)
= [(3 × 2)/ (3 + 2)] × 5
= 6 KilometerUnattemptedRequired distance = [(Product of Two speeds)/(Addition of two speed)]× (Total time taken)
= [(3 × 2)/ (3 + 2)] × 5
= 6 Kilometer  Question 12 of 12
12. Question
1 pointsA motor car does a journey in 10 hours, the first half at 21 kilometer/hrs. and the second half at 24 kilometer/hrs. What is the total distance of the journey?
CorrectThe Required distance = [(Product of Two speeds)/(Addition of two speed)] × (Total time taken) × 2
= [(21 × 24)/ (21 + 24)] × 10 × 2
= 224 KilometerIncorrectThe Required distance = [(Product of Two speeds)/(Addition of two speed)] × (Total time taken) × 2
= [(21 × 24)/ (21 + 24)] × 10 × 2
= 224 KilometerUnattemptedThe Required distance = [(Product of Two speeds)/(Addition of two speed)] × (Total time taken) × 2
= [(21 × 24)/ (21 + 24)] × 10 × 2
= 224 Kilometer