Last Updated on Mar 14, 2023
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Information
Name: Time and Distance mcq quiz – Level 2
Subject: Quantitative Aptitude
Topic: Speed Time and Distance
Questions: 12 mcq type
Time Allowed: 20 minutes
Language: English
Difficulty Level: 2 out of 10.
Important for: SSC CHSL, Amry, BSF, CRPF, Railways, Bank Clerk and 12th level competitions, 8th, 9th, 10th class school students.
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| Pos. | Name | Entered on | Points | Result |
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- Review
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Question 1 of 12
1. Question
1 pointsBy walking 2/7 of his usual speed Ramesh is 15 minute late to his working timing. What is his usual time to cover the distance?
Correct
Explanation:
Usual Time = Late time / [(1 ÷ 2/7-1))]
= 15 / (7/2 – 1)
= (15 × 2) / 5
= 6 minutesIncorrect
Explanation:
Usual Time = Late time / [(1 ÷ 2/7-1))]
= 15 / (7/2 – 1)
= (15 × 2) / 5
= 6 minutesUnattempted
Explanation:
Usual Time = Late time / [(1 ÷ 2/7-1))]
= 15 / (7/2 – 1)
= (15 × 2) / 5
= 6 minutes -
Question 2 of 12
2. Question
1 pointsBy running 4/3 of his usual speed, a person improves his timing by 10 minutes. What his usual time to cover the distance?
Correct
Explanation:
Usual Time = Improved time / [(1 – 1 ÷ 4/3))]
= 10 / (1 – 3/4)
= (10 × 4) / 1
= 40 minutesIncorrect
Explanation:
Usual Time = Improved time / [(1 – 1 ÷ 4/3))]
= 10 / (1 – 3/4)
= (10 × 4) / 1
= 40 minutesUnattempted
Explanation:
Usual Time = Improved time / [(1 – 1 ÷ 4/3))]
= 10 / (1 – 3/4)
= (10 × 4) / 1
= 40 minutes -
Question 3 of 12
3. Question
1 pointsTwo man A and B start form a place P walking at 3 kilometer and 3.5 kilometer an hour respectively. How many kilometers will they be apart at the end of 3 hours of journey when they are walking in the opposite direction?
Correct
When they walk in opposite direction, they will be (3 + 3.5 = 6.5) kilometer apart in one hour.
∴ Required distance = 6.5 × 3 = 19.5 kilometerIncorrect
When they walk in opposite direction, they will be (3 + 3.5 = 6.5) kilometer apart in one hour.
∴ Required distance = 6.5 × 3 = 19.5 kilometerUnattempted
When they walk in opposite direction, they will be (3 + 3.5 = 6.5) kilometer apart in one hour.
∴ Required distance = 6.5 × 3 = 19.5 kilometer -
Question 4 of 12
4. Question
1 pointsTwo man A and B start form a place P walking at 3 kilometer and 3.5 kilometer an hour respectively. How many kilometers will they be apart at the end of 3 hours of journey when they are walking in the same direction?
Correct
When they walk in same direction, they will be (|3 – 3.5| = 0.5) kilometer apart in one hour.
∴ Required distance = 0.5 × 3 = 1.5 kilometerIncorrect
When they walk in same direction, they will be (|3 – 3.5| = 0.5) kilometer apart in one hour.
∴ Required distance = 0.5 × 3 = 1.5 kilometerUnattempted
When they walk in same direction, they will be (|3 – 3.5| = 0.5) kilometer apart in one hour.
∴ Required distance = 0.5 × 3 = 1.5 kilometer -
Question 5 of 12
5. Question
1 pointsA train covers certain distance within 50 minutes, if it runs at a speed of 48 km/h on an average. The speed at which the train must run to reduce the time of the journey to 40 minutes will be?
Correct
Time to cover the distance by train (T) = 50/60 hours = 5/6 hours
Speed of the train to cover the distance (S) = 48 km/h
distance = S × T
= 48 × (5/6)
= 40km
New time to cover the distance = 40/60 hours
= 2/3 hours
New speed of the train (S) = D / T
= 40 / (2/3) km/h
= 60 km/hIncorrect
Time to cover the distance by train (T) = 50/60 hours = 5/6 hours
Speed of the train to cover the distance (S) = 48 km/h
distance = S × T
= 48 × (5/6)
= 40km
New time to cover the distance = 40/60 hours
= 2/3 hours
New speed of the train (S) = D / T
= 40 / (2/3) km/h
= 60 km/hUnattempted
Time to cover the distance by train (T) = 50/60 hours = 5/6 hours
Speed of the train to cover the distance (S) = 48 km/h
distance = S × T
= 48 × (5/6)
= 40km
New time to cover the distance = 40/60 hours
= 2/3 hours
New speed of the train (S) = D / T
= 40 / (2/3) km/h
= 60 km/h -
Question 6 of 12
6. Question
1 pointsBy running 13/11 of his usual speed a old lady is 18 minute improved to attend a doctor appointment. What is his usual time to cover the distance?
Correct
Usual Time = Improved time / [(1 – 1 ÷ 13/11))]
= 18 / (1 – 11/13)
= (18 × 13) / 2
= 117 minutes
= 1 hrs. 57 minutesIncorrect
Usual Time = Improved time / [(1 – 1 ÷ 13/11))]
= 18 / (1 – 11/13)
= (18 × 13) / 2
= 117 minutes
= 1 hrs. 57 minutesUnattempted
Usual Time = Improved time / [(1 – 1 ÷ 13/11))]
= 18 / (1 – 11/13)
= (18 × 13) / 2
= 117 minutes
= 1 hrs. 57 minutes -
Question 7 of 12
7. Question
1 pointsTwo man A and B start form a place P walking at 3 kilometer and 3.5 kilometer an hour respectively. What time will they take to be 16 kilometer apart when they are walking in the opposite direction?
Correct
When they walk in opposite direction, they will be (3 + 3.5 = 6.5) kilometer apart in one hour.
∴ Required time = 16 / 6.5 = 2.46 hoursIncorrect
When they walk in opposite direction, they will be (3 + 3.5 = 6.5) kilometer apart in one hour.
∴ Required time = 16 / 6.5 = 2.46 hoursUnattempted
When they walk in opposite direction, they will be (3 + 3.5 = 6.5) kilometer apart in one hour.
∴ Required time = 16 / 6.5 = 2.46 hours -
Question 8 of 12
8. Question
1 pointsA train travelling 25 kilometer an hour leaves Delhi at 9 A.M. and another train travelling 35 kilometer an hour start at 2 P.M in the same direction. How many kilometers from Delhi will they be together?
Correct
Meeting point’s distance from the starting point =
[(Product of speed) / (Difference of speed)] × (Difference in time)
∴Required distance = [(25 × 35) / (35 – 25)] × (2 P.M – 9 A.M)
= (25 × 35 × 5) / 10
= 437.5 KilometerIncorrect
Meeting point’s distance from the starting point =
[(Product of speed) / (Difference of speed)] × (Difference in time)
∴Required distance = [(25 × 35) / (35 – 25)] × (2 P.M – 9 A.M)
= (25 × 35 × 5) / 10
= 437.5 KilometerUnattempted
Meeting point’s distance from the starting point =
[(Product of speed) / (Difference of speed)] × (Difference in time)
∴Required distance = [(25 × 35) / (35 – 25)] × (2 P.M – 9 A.M)
= (25 × 35 × 5) / 10
= 437.5 Kilometer -
Question 9 of 12
9. Question
1 pointsA motor car takes 50 seconds to travel 500 meters. What is its speed in km per hour?
Correct
Speed in m/s = 500 / 50 = 10
∴ Speed in km/hr = 10 × (18/5) = 36 km/hr.Incorrect
Speed in m/s = 500 / 50 = 10
∴ Speed in km/hr = 10 × (18/5) = 36 km/hr.Unattempted
Speed in m/s = 500 / 50 = 10
∴ Speed in km/hr = 10 × (18/5) = 36 km/hr. -
Question 10 of 12
10. Question
1 pointsWhat is the length of the bridge which a man riding 15 kilometer an hour can cross in 5 minutes?
Correct
Distance cover in 5 minutes = (15 / 60) × 5 = (15 / 12) = 5/4 kilometer = 1250 meters
Incorrect
Distance cover in 5 minutes = (15 / 60) × 5 = (15 / 12) = 5/4 kilometer = 1250 meters
Unattempted
Distance cover in 5 minutes = (15 / 60) × 5 = (15 / 12) = 5/4 kilometer = 1250 meters
-
Question 11 of 12
11. Question
1 pointsI walk a certain distance and ride back and take 13/2 hour altogether. I could walk both ways in 31/4 hours. How long would it take me to ride both ways?
Correct
Walking + Riding = 13/2 hrs
Walking + Walking = 2 walking = 31/4 hrs
by solving these two equation we get;
2 Riding = 13 – 31 / 4 = 21 / 4 = 5 hrs. 15 min.Incorrect
Walking + Riding = 13/2 hrs
Walking + Walking = 2 walking = 31/4 hrs
by solving these two equation we get;
2 Riding = 13 – 31 / 4 = 21 / 4 = 5 hrs. 15 min.Unattempted
Walking + Riding = 13/2 hrs
Walking + Walking = 2 walking = 31/4 hrs
by solving these two equation we get;
2 Riding = 13 – 31 / 4 = 21 / 4 = 5 hrs. 15 min. -
Question 12 of 12
12. Question
1 pointsTwo persons M and N start form a place of P walking at 4.48 kilometer and 3.96 kilometer an hour respectively. How many kilometers will they be apart at the end of 5 hours of journey when they are walking in the same direction?
Correct
When they walk in same direction, they will be (|4.48 – 3.96| = 0.52) kilometer apart in one hour.
∴ Required time = 18 / 0.52 = 34.61 hoursIncorrect
When they walk in same direction, they will be (|4.48 – 3.96| = 0.52) kilometer apart in one hour.
∴ Required time = 18 / 0.52 = 34.61 hoursUnattempted
When they walk in same direction, they will be (|4.48 – 3.96| = 0.52) kilometer apart in one hour.
∴ Required time = 18 / 0.52 = 34.61 hours
