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Name : Boats and Streams Test 1
Subject : Aptitude
Topic : Boats and Streams
Questions: 15 Objective type mcq
Time Allowed : 25 minutes
Important for : IIT JEE, High School students, SSC, IBPS, SBI, RBI and other competitions.
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 Question 1 of 15
1. Question
1 pointsIn one hour, a boat goes 11 km along the stream and 5 km against the stream. The speed of the boat in still water (in km/hr) is:
CorrectSpeed in still water == ½ (11+5) kmph= 8 kmph.
IncorrectSpeed in still water == ½ (11+5) kmph= 8 kmph.
UnattemptedSpeed in still water == ½ (11+5) kmph= 8 kmph.
 Question 2 of 15
2. Question
1 pointsA man can row upstream at 8 kmph and downstream at 13 kmph. The speed of the stream is:
Correctspeed of stream = ½(138) kmph =2.5 kmph
Incorrectspeed of stream = ½(138) kmph =2.5 kmph
Unattemptedspeed of stream = ½(138) kmph =2.5 kmph
 Question 3 of 15
3. Question
1 pointsA man rows downstream 32 km and 14 km upstream. If he takes 6 hours to cover each distance, then the velocity (in kmph) of the current is:
CorrectRate downstream = (32/6) kmph; Rate upstream = (14/6) kmph. Velocity.Velocity of current = ½(32/614/6) kmph = 3/2 kmph =1.5 kmph.
IncorrectRate downstream = (32/6) kmph; Rate upstream = (14/6) kmph. Velocity.Velocity of current = ½(32/614/6) kmph = 3/2 kmph =1.5 kmph.
UnattemptedRate downstream = (32/6) kmph; Rate upstream = (14/6) kmph. Velocity.Velocity of current = ½(32/614/6) kmph = 3/2 kmph =1.5 kmph.
 Question 4 of 15
4. Question
1 pointsA boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance, upstream, it takes 4 hours. What is the speed of the boat in still water?
CorrectRate downstream =(16/2) kmph = 8 kmph ; Rate upstream = (16/4) kmph = 4 kmph.
Speed in still water = ½ (8+4) kmph = 6 kmph.IncorrectRate downstream =(16/2) kmph = 8 kmph ; Rate upstream = (16/4) kmph = 4 kmph.
Speed in still water = ½ (8+4) kmph = 6 kmph.UnattemptedRate downstream =(16/2) kmph = 8 kmph ; Rate upstream = (16/4) kmph = 4 kmph.
Speed in still water = ½ (8+4) kmph = 6 kmph.  Question 5 of 15
5. Question
1 pointsA boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
CorrectRate downstream = [(1/10)×60] km/hr = 6 km/hr ; Rate upstream = 2 km/hr.
Speed in still water =1/2(6+2) km/hr =4 km/hr.
Required time =(5/4) hrs = 5/4 hrs = 1 hr 15 min.IncorrectRate downstream = [(1/10)×60] km/hr = 6 km/hr ; Rate upstream = 2 km/hr.
Speed in still water =1/2(6+2) km/hr =4 km/hr.
Required time =(5/4) hrs = 5/4 hrs = 1 hr 15 min.UnattemptedRate downstream = [(1/10)×60] km/hr = 6 km/hr ; Rate upstream = 2 km/hr.
Speed in still water =1/2(6+2) km/hr =4 km/hr.
Required time =(5/4) hrs = 5/4 hrs = 1 hr 15 min.  Question 6 of 15
6. Question
1 pointsA man can row threequarters of a kilometer against the stream in 45/4 minutes. The speed (in km/hr) of the man in still water is:
CorrectRate upstream = (750/675) m /sec =10/9 m/ sec ;
Rate downstream = (750/450) m/ sec = 5/3 m/sec.
Rate in still water =1/2[(10/9)+(5/3)] m/sec =25/18 m/ sec = [(25/18)×(18/5)] km / hr = 5 km /hr.IncorrectRate upstream = (750/675) m /sec =10/9 m/ sec ;
Rate downstream = (750/450) m/ sec = 5/3 m/sec.
Rate in still water =1/2[(10/9)+(5/3)] m/sec =25/18 m/ sec = [(25/18)×(18/5)] km / hr = 5 km /hr.UnattemptedRate upstream = (750/675) m /sec =10/9 m/ sec ;
Rate downstream = (750/450) m/ sec = 5/3 m/sec.
Rate in still water =1/2[(10/9)+(5/3)] m/sec =25/18 m/ sec = [(25/18)×(18/5)] km / hr = 5 km /hr.  Question 7 of 15
7. Question
1 pointsA man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of boat (in still water) and the stream is :
CorrectLet man’s rate upstream be x kmph. Then, his rate downstream = 2x kmph.
(Speed in still water)
(Speed of stream) = [(2X+X)/2] : [(2XX)/2] = 3X/2 : X/2
= 3:1IncorrectLet man’s rate upstream be x kmph. Then, his rate downstream = 2x kmph.
(Speed in still water)
(Speed of stream) = [(2X+X)/2] : [(2XX)/2] = 3X/2 : X/2
= 3:1UnattemptedLet man’s rate upstream be x kmph. Then, his rate downstream = 2x kmph.
(Speed in still water)
(Speed of stream) = [(2X+X)/2] : [(2XX)/2] = 3X/2 : X/2
= 3:1  Question 8 of 15
8. Question
1 pointsA boat running upstream takes 8 hour 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively ?
CorrectLet the man’ rate upstream be x kmph and that downstream be y kmph. Then, Distance covered upstream in 8 hrs 48 min. = Distance covered downstream in 4 hrs.
(X×44/5) = (Y×4) 44/5x = 4y Y = 11/5 x.
Required ratio = = [(y+x)/2] : [(yx)/2]
= (16x/5×1/2) : (6x/5×1/2)
=8/5 : 3/5
= 8 : 3.IncorrectLet the man’ rate upstream be x kmph and that downstream be y kmph. Then, Distance covered upstream in 8 hrs 48 min. = Distance covered downstream in 4 hrs.
(X×44/5) = (Y×4) 44/5x = 4y Y = 11/5 x.
Required ratio = = [(y+x)/2] : [(yx)/2]
= (16x/5×1/2) : (6x/5×1/2)
=8/5 : 3/5
= 8 : 3.UnattemptedLet the man’ rate upstream be x kmph and that downstream be y kmph. Then, Distance covered upstream in 8 hrs 48 min. = Distance covered downstream in 4 hrs.
(X×44/5) = (Y×4) 44/5x = 4y Y = 11/5 x.
Required ratio = = [(y+x)/2] : [(yx)/2]
= (16x/5×1/2) : (6x/5×1/2)
=8/5 : 3/5
= 8 : 3.  Question 9 of 15
9. Question
1 pointsIf a boat goes 7 km upstream in 42 minutes and the speed of the stream is 3 kmph, then the speed of boat in still water is :
CorrectRate upstream = (7/42× 60) kmph = kmph .
Speed of stream = 3 kmph.
Let speed in still water be x km / hr. Then, speed upstream = (x3) km /hr.
X3 = 10 or x =13 km / hr.IncorrectRate upstream = (7/42× 60) kmph = kmph .
Speed of stream = 3 kmph.
Let speed in still water be x km / hr. Then, speed upstream = (x3) km /hr.
X3 = 10 or x =13 km / hr.UnattemptedRate upstream = (7/42× 60) kmph = kmph .
Speed of stream = 3 kmph.
Let speed in still water be x km / hr. Then, speed upstream = (x3) km /hr.
X3 = 10 or x =13 km / hr.  Question 10 of 15
10. Question
1 pointsA man ‘s speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man’s speed against the current is :
CorrectMan’s rate in still water = (152.5) km / hr = 12.5 km/ hr.
Man’s rate against the current = (12.52.5) km/ hr = 10 km/hr.IncorrectMan’s rate in still water = (152.5) km / hr = 12.5 km/ hr.
Man’s rate against the current = (12.52.5) km/ hr = 10 km/hr.UnattemptedMan’s rate in still water = (152.5) km / hr = 12.5 km/ hr.
Man’s rate against the current = (12.52.5) km/ hr = 10 km/hr.  Question 11 of 15
11. Question
1 pointsIf a man rows at the rate of 5 kmph in still water and his rate against the current is 3.5 kmph, then the man’s rate along the current is:
CorrectLet the rate along the current be x kmph. Then, ½(x+3.5) = 5 or x = 6.5 kmph.
IncorrectLet the rate along the current be x kmph. Then, ½(x+3.5) = 5 or x = 6.5 kmph.
UnattemptedLet the rate along the current be x kmph. Then, ½(x+3.5) = 5 or x = 6.5 kmph.
 Question 12 of 15
12. Question
1 pointsA boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
CorrectSpeed downstream = (13+4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = (68/17) hrs = 4 hrs.IncorrectSpeed downstream = (13+4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = (68/17) hrs = 4 hrs.UnattemptedSpeed downstream = (13+4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = (68/17) hrs = 4 hrs.  Question 13 of 15
13. Question
1 pointsSpeed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at distance of 105 km and comes back to the starting point.
CorrectSpeed upstream = 7.5 kmph; Speed downstream = 10.5 kmph.
Total time taken = [(105/7.5)+(105/10.5)] hours = 24 hours.IncorrectSpeed upstream = 7.5 kmph; Speed downstream = 10.5 kmph.
Total time taken = [(105/7.5)+(105/10.5)] hours = 24 hours.UnattemptedSpeed upstream = 7.5 kmph; Speed downstream = 10.5 kmph.
Total time taken = [(105/7.5)+(105/10.5)] hours = 24 hours.  Question 14 of 15
14. Question
1 pointsThe speed of a boat in still water is 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is:
CorrectSpeed downstream = (15+3) kmph = 18 kmph.
Distance traveled = (1092/60) km = 3.6 km.IncorrectSpeed downstream = (15+3) kmph = 18 kmph.
Distance traveled = (1092/60) km = 3.6 km.UnattemptedSpeed downstream = (15+3) kmph = 18 kmph.
Distance traveled = (1092/60) km = 3.6 km.  Question 15 of 15
15. Question
1 pointsA man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to a place and come back, how far is the place?
Correct: Speed downstream = (5+1) kmph; Speed upstream = (51) kmph = 4 kmph.
Let the required distance be x km.Incorrect: Speed downstream = (5+1) kmph; Speed upstream = (51) kmph = 4 kmph.
Let the required distance be x km.Unattempted: Speed downstream = (5+1) kmph; Speed upstream = (51) kmph = 4 kmph.
Let the required distance be x km.