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Quiz Description :
Name: Race and Games – Aptitude Practice Test – 2
Subject: Aptitude
Topic: Race and Games Problems
Questions: 9 Objective type
Time Allowed: 18 Minutes
Important for: RBI, SBI and IBPS Bank exams, SSC CGL, State Competitions, Army, CRPF, BSF and Job aptitude test etc.
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 Question 1 of 15
1. Question
1 pointsIn a Kilometer race A beats B by 25 or 5 seconds. Then find out the time taken by A to complete the race.
CorrectB runs 25 meter in 5 seconds.
∴ B’s time to cover 1 kilometer = (5 / 25) × 100
= 200 secondsA’s time to cover 1 kilometer distance = 200 – 5
= 195 seconds
= 3 minutes 15 secondsIncorrectB runs 25 meter in 5 seconds.
∴ B’s time to cover 1 kilometer = (5 / 25) × 100
= 200 secondsA’s time to cover 1 kilometer distance = 200 – 5
= 195 seconds
= 3 minutes 15 secondsUnattemptedB runs 25 meter in 5 seconds.
∴ B’s time to cover 1 kilometer = (5 / 25) × 100
= 200 secondsA’s time to cover 1 kilometer distance = 200 – 5
= 195 seconds
= 3 minutes 15 seconds  Question 2 of 15
2. Question
1 pointsIn a race of 30 meter, A beats B by 15 meter or 5 seconds. A’s time over the course is:
Correct15 meter is covered by B’s in 15 seconds.
∴ 300 meter is covered by B in (5/15 × 300) = 100 seconds
∴ A takes 100 – 5 = 95 secondsIncorrect15 meter is covered by B’s in 15 seconds.
∴ 300 meter is covered by B in (5/15 × 300) = 100 seconds
∴ A takes 100 – 5 = 95 secondsUnattempted15 meter is covered by B’s in 15 seconds.
∴ 300 meter is covered by B in (5/15 × 300) = 100 seconds
∴ A takes 100 – 5 = 95 seconds  Question 3 of 15
3. Question
1 pointsA can run 500 meter in 30 seconds and B in 35 seconds. How many meter start can A give to B in a Kilometer race so that the race may end in a deadheat?
CorrectTime taken by A to run one kilometer = 30 × 2 = 60 seconds
Time taken by B to run one kilometer = 35 × 2 = 70 seconds
∴ A can give B a start of (70 – 60) = 10 seconds.
In 35 seconds B runs 500 meter
∴ In 10 seconds B runds = (500/35) × 10 = 1000/7
So, A can give B a start of 1000/7 meters in a kilometer race.IncorrectTime taken by A to run one kilometer = 30 × 2 = 60 seconds
Time taken by B to run one kilometer = 35 × 2 = 70 seconds
∴ A can give B a start of (70 – 60) = 10 seconds.
In 35 seconds B runs 500 meter
∴ In 10 seconds B runds = (500/35) × 10 = 1000/7
So, A can give B a start of 1000/7 meters in a kilometer race.UnattemptedTime taken by A to run one kilometer = 30 × 2 = 60 seconds
Time taken by B to run one kilometer = 35 × 2 = 70 seconds
∴ A can give B a start of (70 – 60) = 10 seconds.
In 35 seconds B runs 500 meter
∴ In 10 seconds B runds = (500/35) × 10 = 1000/7
So, A can give B a start of 1000/7 meters in a kilometer race.  Question 4 of 15
4. Question
1 pointsA runs 11/8 times as fast as B. If A gives B a start of 120 meter and they reach the goal at the same time, the goal is at a distance of:
CorrectThe speed of A and B are in the ratio 11 : 8.
Let, speeds by 11s and 8 s (in meter/seconds)
Let, race be of ‘x’ meter.
Then, time taken by A to run x meter is same as that of B to run (x – 120) meter.
∴ (x / 11s) = [(x – 120) / 8s]
∴ 3x = 11 × 120
∴ x = 440.IncorrectThe speed of A and B are in the ratio 11 : 8.
Let, speeds by 11s and 8 s (in meter/seconds)
Let, race be of ‘x’ meter.
Then, time taken by A to run x meter is same as that of B to run (x – 120) meter.
∴ (x / 11s) = [(x – 120) / 8s]
∴ 3x = 11 × 120
∴ x = 440.UnattemptedThe speed of A and B are in the ratio 11 : 8.
Let, speeds by 11s and 8 s (in meter/seconds)
Let, race be of ‘x’ meter.
Then, time taken by A to run x meter is same as that of B to run (x – 120) meter.
∴ (x / 11s) = [(x – 120) / 8s]
∴ 3x = 11 × 120
∴ x = 440.  Question 5 of 15
5. Question
1 pointsIn a game of 100 points, A can give B 20 points and C 28 points. Number of points B can give C in a game of 100 points is:
CorrectA scores 100 while B scores 100 – 20 = 80 and
C scores 100 – 28 = 72
∴ while B scores 10, C scores (72 / 80) × 100 = 90
∴ B can give C 100 – 90 = 10 pointsIncorrectA scores 100 while B scores 100 – 20 = 80 and
C scores 100 – 28 = 72
∴ while B scores 10, C scores (72 / 80) × 100 = 90
∴ B can give C 100 – 90 = 10 pointsUnattemptedA scores 100 while B scores 100 – 20 = 80 and
C scores 100 – 28 = 72
∴ while B scores 10, C scores (72 / 80) × 100 = 90
∴ B can give C 100 – 90 = 10 points  Question 6 of 15
6. Question
1 pointsA’s speed is 3/2 times of B’s. In a race A gives B a start of 300 meter. How long should the race course be so that reaches the winning post simultaneously?
CorrectA’s speed : B’s speed
= 3/2 : 1 = 3 : 2
It means that in a race of 3 meter, A gains (3 – 2).
= one meter over B.
One meter is gained by A in a race of 3 meter.
∴ 300 meter is gained by A in a race of = (3 × 1) × 300 = 900 meter.IncorrectA’s speed : B’s speed
= 3/2 : 1 = 3 : 2
It means that in a race of 3 meter, A gains (3 – 2).
= one meter over B.
One meter is gained by A in a race of 3 meter.
∴ 300 meter is gained by A in a race of = (3 × 1) × 300 = 900 meter.UnattemptedA’s speed : B’s speed
= 3/2 : 1 = 3 : 2
It means that in a race of 3 meter, A gains (3 – 2).
= one meter over B.
One meter is gained by A in a race of 3 meter.
∴ 300 meter is gained by A in a race of = (3 × 1) × 300 = 900 meter.  Question 7 of 15
7. Question
1 pointsIn a race of 600 meter, A can beat B by 60 meter, and in a race of 500 meter, B can beat C by 50 meter. By how many meter will A beat C in a race of 400 meter?
CorrectClearly, if A runs 600 meters, B runs = 540 meters
∴ If A runs 400 meter, B runs = [(540 / 600) × 400]
= 360 meter
Again, when B runs 500 meter, C runs = 450 meter
∴ When B runs 360 meter, C runs = [(450/500)×360]meter = 324 meter.IncorrectClearly, if A runs 600 meters, B runs = 540 meters
∴ If A runs 400 meter, B runs = [(540 / 600) × 400]
= 360 meter
Again, when B runs 500 meter, C runs = 450 meter
∴ When B runs 360 meter, C runs = [(450/500)×360]meter = 324 meter.UnattemptedClearly, if A runs 600 meters, B runs = 540 meters
∴ If A runs 400 meter, B runs = [(540 / 600) × 400]
= 360 meter
Again, when B runs 500 meter, C runs = 450 meter
∴ When B runs 360 meter, C runs = [(450/500)×360]meter = 324 meter.  Question 8 of 15
8. Question
1 pointsIn a 100 meter race, A runs at 5 Km/h. A gives B a start of 8 meter and still beasts him by 8 second. Find out the speed of B.
CorrectTime taken by A to cover 100 meter = 100 + [5 × (5/18)] = 72 seconds
∴ B covers (100 – 8) or, 92 meter in (72 + 8) or, 80 seconds.
∴ Speed of B = (92/80) × (16/5) = 4.14 Km/hrs.IncorrectTime taken by A to cover 100 meter = 100 + [5 × (5/18)] = 72 seconds
∴ B covers (100 – 8) or, 92 meter in (72 + 8) or, 80 seconds.
∴ Speed of B = (92/80) × (16/5) = 4.14 Km/hrs.UnattemptedTime taken by A to cover 100 meter = 100 + [5 × (5/18)] = 72 seconds
∴ B covers (100 – 8) or, 92 meter in (72 + 8) or, 80 seconds.
∴ Speed of B = (92/80) × (16/5) = 4.14 Km/hrs.  Question 9 of 15
9. Question
1 pointsIn a game, A can give B 20 points, A can give C 32 points and B can give C 15 points. How many points make the game?
CorrectAssume that ‘x’ points make the game.
It is clear, when A scores x points, B scores (x – 20) points and C scores (x – 32) points.
Now, when B scores x points, C scores (x – 15) points.
When B scores (x – 20) points
∴ C scores [(x – 15) × (x 20)/x] points
∴ [(x – 15) × (x 20)/x] = x – 20 or x = 100IncorrectAssume that ‘x’ points make the game.
It is clear, when A scores x points, B scores (x – 20) points and C scores (x – 32) points.
Now, when B scores x points, C scores (x – 15) points.
When B scores (x – 20) points
∴ C scores [(x – 15) × (x 20)/x] points
∴ [(x – 15) × (x 20)/x] = x – 20 or x = 100UnattemptedAssume that ‘x’ points make the game.
It is clear, when A scores x points, B scores (x – 20) points and C scores (x – 32) points.
Now, when B scores x points, C scores (x – 15) points.
When B scores (x – 20) points
∴ C scores [(x – 15) × (x 20)/x] points
∴ [(x – 15) × (x 20)/x] = x – 20 or x = 100  Question 10 of 15
10. Question
1 pointsIn a race of 600 meter, A can beat B by 60 meter and in a race of 500 meter, B can beat C by 50 meter. By how many meters will A beat C in a race of 400 meter?
CorrectIf A runs 600 meter, B runs 600 – 60 or, 540 meter.
If A runs 400 meter, B runs = (540 × 400) / 600 = 360 meter.
Now, when B runs 500 meter, C runs 500 – 50 = 450 meter
∴ When B runs 360 meter, C runs = (450 × 360) / 500 = 324 meter.IncorrectIf A runs 600 meter, B runs 600 – 60 or, 540 meter.
If A runs 400 meter, B runs = (540 × 400) / 600 = 360 meter.
Now, when B runs 500 meter, C runs 500 – 50 = 450 meter
∴ When B runs 360 meter, C runs = (450 × 360) / 500 = 324 meter.UnattemptedIf A runs 600 meter, B runs 600 – 60 or, 540 meter.
If A runs 400 meter, B runs = (540 × 400) / 600 = 360 meter.
Now, when B runs 500 meter, C runs 500 – 50 = 450 meter
∴ When B runs 360 meter, C runs = (450 × 360) / 500 = 324 meter.  Question 11 of 15
11. Question
1 pointsIn a game A can give B 25 points in 75 and C 18 points in 90. How many points can C give B in a game of 120?
CorrectWhen A scores 75 points, B scores 50 points.
When A scores 90 points, C scores (90 – 18) = 72 points.
∴ When A scores 75 points, C scores = (72/90)×75 = 60 points
A : B : C = 75 : 50 : 60
C : B = (60 / 50) = (120 / 100).IncorrectWhen A scores 75 points, B scores 50 points.
When A scores 90 points, C scores (90 – 18) = 72 points.
∴ When A scores 75 points, C scores = (72/90)×75 = 60 points
A : B : C = 75 : 50 : 60
C : B = (60 / 50) = (120 / 100).UnattemptedWhen A scores 75 points, B scores 50 points.
When A scores 90 points, C scores (90 – 18) = 72 points.
∴ When A scores 75 points, C scores = (72/90)×75 = 60 points
A : B : C = 75 : 50 : 60
C : B = (60 / 50) = (120 / 100).  Question 12 of 15
12. Question
1 pointsA and B run a 5 kilometer race on a round course of 400 meter. If their speeds be in the ratio 5 : 4, then how often does the winner pass the other?
CorrectWhen A makes 5 rounds, B makes 4 rounds.
In order to pass each other, the difference in number of rounds made by each must be one. Here, A passes B each time, when A makes 5 rounds.
Distance covered by A is 5 rounds = [(5 × 400)/ 100] = 2 kilometer.
In covering 2 kilometer, A passes B one time.
∴ In covering 5 kilometer, A passes B = (5/2) = 2.5 times.IncorrectWhen A makes 5 rounds, B makes 4 rounds.
In order to pass each other, the difference in number of rounds made by each must be one. Here, A passes B each time, when A makes 5 rounds.
Distance covered by A is 5 rounds = [(5 × 400)/ 100] = 2 kilometer.
In covering 2 kilometer, A passes B one time.
∴ In covering 5 kilometer, A passes B = (5/2) = 2.5 times.UnattemptedWhen A makes 5 rounds, B makes 4 rounds.
In order to pass each other, the difference in number of rounds made by each must be one. Here, A passes B each time, when A makes 5 rounds.
Distance covered by A is 5 rounds = [(5 × 400)/ 100] = 2 kilometer.
In covering 2 kilometer, A passes B one time.
∴ In covering 5 kilometer, A passes B = (5/2) = 2.5 times.  Question 13 of 15
13. Question
1 pointsIn a 500 meter race, the ration of speeds of two contestants A and B is 3 : 4. A has a start of 140 meter. Than, A wins by;
CorrectTo reach the winning post, A will have to cover a distance of (500 – 140), i.e., 360 meter.
While A covers 3 meter, B covers [(4/3) ×360] = 480 meter.
So, A reaches the winning post while B remains 20 meter behind.
∴ A wins by 20 meter.IncorrectTo reach the winning post, A will have to cover a distance of (500 – 140), i.e., 360 meter.
While A covers 3 meter, B covers [(4/3) ×360] = 480 meter.
So, A reaches the winning post while B remains 20 meter behind.
∴ A wins by 20 meter.UnattemptedTo reach the winning post, A will have to cover a distance of (500 – 140), i.e., 360 meter.
While A covers 3 meter, B covers [(4/3) ×360] = 480 meter.
So, A reaches the winning post while B remains 20 meter behind.
∴ A wins by 20 meter.  Question 14 of 15
14. Question
1 pointsIn a Kilometer race A beats B 100 meter C by 200 meter. By how many can B beat C in a race of 1350 meter?
CorrectWhile A runs 1000 meter,
B runs 1000 – 100 = 900 meter,
and C runs 1000 – 200 = 800 meter.
∴ While B runs 900 meter; C runs = 800 meter.
∴ While B runs 1350 meter ; C runs = [(800/900)×1350] = 1200 meter
∴ B can beat C by 1350 – 1200 = 150 meter.IncorrectWhile A runs 1000 meter,
B runs 1000 – 100 = 900 meter,
and C runs 1000 – 200 = 800 meter.
∴ While B runs 900 meter; C runs = 800 meter.
∴ While B runs 1350 meter ; C runs = [(800/900)×1350] = 1200 meter
∴ B can beat C by 1350 – 1200 = 150 meter.UnattemptedWhile A runs 1000 meter,
B runs 1000 – 100 = 900 meter,
and C runs 1000 – 200 = 800 meter.
∴ While B runs 900 meter; C runs = 800 meter.
∴ While B runs 1350 meter ; C runs = [(800/900)×1350] = 1200 meter
∴ B can beat C by 1350 – 1200 = 150 meter.  Question 15 of 15
15. Question
1 pointsTwo boys, A and B at 9.2 and 6 kilometer an hour. A having 190 meter start. The course being 1 kilometer, B wins by a distance of
CorrectSpeeds (in meter/seconds) of A is = (9/2)× (5/18) = (5/4)
Speeds (in meter/seconds) of B is = 6 × (5/18) = (5/3)
A has a start of 190 meter. So, A has to run 1000 – 190 = 810 meter, while B 1000 meter.Time taken by B to cover 1000 meter = (3/5) × 1000 = 600 seconds.
In this time, A covers = (5/4)×600 = 750 meter
So, B reaches the winning post while A remains 810 – 750 = 60 meter behind.
∴ B wins by 60 meter.IncorrectSpeeds (in meter/seconds) of A is = (9/2)× (5/18) = (5/4)
Speeds (in meter/seconds) of B is = 6 × (5/18) = (5/3)
A has a start of 190 meter. So, A has to run 1000 – 190 = 810 meter, while B 1000 meter.Time taken by B to cover 1000 meter = (3/5) × 1000 = 600 seconds.
In this time, A covers = (5/4)×600 = 750 meter
So, B reaches the winning post while A remains 810 – 750 = 60 meter behind.
∴ B wins by 60 meter.UnattemptedSpeeds (in meter/seconds) of A is = (9/2)× (5/18) = (5/4)
Speeds (in meter/seconds) of B is = 6 × (5/18) = (5/3)
A has a start of 190 meter. So, A has to run 1000 – 190 = 810 meter, while B 1000 meter.Time taken by B to cover 1000 meter = (3/5) × 1000 = 600 seconds.
In this time, A covers = (5/4)×600 = 750 meter
So, B reaches the winning post while A remains 810 – 750 = 60 meter behind.
∴ B wins by 60 meter.