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Quiz Description :
Name: Boats and Stream objective Test – 2
Subject: Aptitude
Topic: Boats and Stream
Questions: 12
Time Allowed: 20 minutes
Important for: SSC ( CGL, CHSL, GD, MTS, JE), IBPS, SBI, RBI ( Clerk, PO, SO, Assistant), IIT- JEE, AIPMT, Aptitude test and other competitions.
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| Pos. | Name | Entered on | Points | Result |
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- Question 1 of 12
1. Question
1 pointsA man can row up-stream at 10 km/hr and down-streams at 16 km/hr. What is the rate of the current.
CorrectRate of current = 1/2(16 -10) = 3 km/hr
IncorrectRate of current = 1/2(16 -10) = 3 km/hr
UnattemptedRate of current = 1/2(16 -10) = 3 km/hr
- Question 2 of 12
2. Question
1 pointsA man swings down-stream 30 km and up-stream 18 km, taking 3 hours catch time. What is the velocity of current?
CorrectMan’s rate down-stream = 30/3 km/hr = 10 km/hr
Man’s rate up-stream = 18/3 km/hr = 6 km/hr
∴ Velocity of stream (current) = ((10 – 6))/2 = 2 km/hrIncorrectMan’s rate down-stream = 30/3 km/hr = 10 km/hr
Man’s rate up-stream = 18/3 km/hr = 6 km/hr
∴ Velocity of stream (current) = ((10 – 6))/2 = 2 km/hrUnattemptedMan’s rate down-stream = 30/3 km/hr = 10 km/hr
Man’s rate up-stream = 18/3 km/hr = 6 km/hr
∴ Velocity of stream (current) = ((10 – 6))/2 = 2 km/hr - Question 3 of 12
3. Question
1 pointsA man can row 6km/hr in still water. It takes him twice as long to row up as to row down the river. What is the rate of the stream?
CorrectLet rate of stream = x km/hr
Then, 6 + x = 2 (6 – x)
or, 3x = 6
∴ x= 6/3 = 2 km/hrIncorrectLet rate of stream = x km/hr
Then, 6 + x = 2 (6 – x)
or, 3x = 6
∴ x= 6/3 = 2 km/hrUnattemptedLet rate of stream = x km/hr
Then, 6 + x = 2 (6 – x)
or, 3x = 6
∴ x= 6/3 = 2 km/hr - Question 4 of 12
4. Question
1 pointsA man can row 6 km/hr in still water. When the river is running at 1.2 km/hr, it takes him 1 hour to row to a place and back. How far is the place?
CorrectRequired distance = ([1 ×(62 – 1.22)])/((2 × 6)) = (36 -1.44)/12 = 3 – 0.12 = 2.88 km.
IncorrectRequired distance = ([1 ×(62 – 1.22)])/((2 × 6)) = (36 -1.44)/12 = 3 – 0.12 = 2.88 km.
UnattemptedRequired distance = ([1 ×(62 – 1.22)])/((2 × 6)) = (36 -1.44)/12 = 3 – 0.12 = 2.88 km.
- Question 5 of 12
5. Question
1 pointsIn a stream running at 2km/hr, a motorboat goes 10km up-stream and back again to the starting point in 55 minutes. What is the speed of the motorboat in still water?
Correct10= 55/60×(x2 – 22)/2x
or, 1200 x = 55 (x2 – 4)
or, 11 x2 – 240 x – 44 = 0
∴ (x – 22)(11 x + 2) = 0
So, x = 22 km/hr (neglecting the –ve value)Incorrect10= 55/60×(x2 – 22)/2x
or, 1200 x = 55 (x2 – 4)
or, 11 x2 – 240 x – 44 = 0
∴ (x – 22)(11 x + 2) = 0
So, x = 22 km/hr (neglecting the –ve value)Unattempted10= 55/60×(x2 – 22)/2x
or, 1200 x = 55 (x2 – 4)
or, 11 x2 – 240 x – 44 = 0
∴ (x – 22)(11 x + 2) = 0
So, x = 22 km/hr (neglecting the –ve value) - Question 6 of 12
6. Question
1 pointsA man can row 30km up-stream and 44 km down-stream in 10 hours. Also, he can row 40 km up-stream and 55km down-stream in 13 hours. What is the rate of the current and the speed of the man in still water?
CorrectBy using cross multiplication formula;
Upstream Down stream Time
30 44 10
40 55 13Upstream speed of man = (30 × 55 – 40 × 44)/(55 × 10 – 44 × 13) = (-110)/(-22) = 5 km/hr
Downstream speed of man = (30 ×55-40 ×44)/(30 ×13-40 ×10) = (-110)/(-10) = 11 km/hr
∴ Speed of man = (5 + 11)/2 = 8 km/hr
and speed of stream = (11 – 5)/2 = 3 km/hr.IncorrectBy using cross multiplication formula;
Upstream Down stream Time
30 44 10
40 55 13Upstream speed of man = (30 × 55 – 40 × 44)/(55 × 10 – 44 × 13) = (-110)/(-22) = 5 km/hr
Downstream speed of man = (30 ×55-40 ×44)/(30 ×13-40 ×10) = (-110)/(-10) = 11 km/hr
∴ Speed of man = (5 + 11)/2 = 8 km/hr
and speed of stream = (11 – 5)/2 = 3 km/hr.UnattemptedBy using cross multiplication formula;
Upstream Down stream Time
30 44 10
40 55 13Upstream speed of man = (30 × 55 – 40 × 44)/(55 × 10 – 44 × 13) = (-110)/(-22) = 5 km/hr
Downstream speed of man = (30 ×55-40 ×44)/(30 ×13-40 ×10) = (-110)/(-10) = 11 km/hr
∴ Speed of man = (5 + 11)/2 = 8 km/hr
and speed of stream = (11 – 5)/2 = 3 km/hr. - Question 7 of 12
7. Question
1 pointsA man can row 15km/hr in still water. It takes him twice as long to row up as to row down the river. What is the rate of the stream?
CorrectLet rate of stream = x km/hr
Then, 15 + x = 2 (15 – x)
or, 3x = 15
∴ x= 15/3 = 5 km/hrIncorrectLet rate of stream = x km/hr
Then, 15 + x = 2 (15 – x)
or, 3x = 15
∴ x= 15/3 = 5 km/hrUnattemptedLet rate of stream = x km/hr
Then, 15 + x = 2 (15 – x)
or, 3x = 15
∴ x= 15/3 = 5 km/hr - Question 8 of 12
8. Question
1 pointsA man can row 9 km/hr in still water. When the river is running at 2.5 km/hr, it takes him 3 hour to row to a place and back. How far is the place?
CorrectRequired distance = ([3 ×(92 – 2.52)])/((2 × 9)) = (3 × (81 -6.25))/18 = 224.25/18 = 12.46 km.
IncorrectRequired distance = ([3 ×(92 – 2.52)])/((2 × 9)) = (3 × (81 -6.25))/18 = 224.25/18 = 12.46 km.
UnattemptedRequired distance = ([3 ×(92 – 2.52)])/((2 × 9)) = (3 × (81 -6.25))/18 = 224.25/18 = 12.46 km.
- Question 9 of 12
9. Question
1 pointsA boat covers 24 km upstream and 36 km downstream in 6 hours, while it covers 36 km upstream and 24 km downstream in 6.5 hours. Find the velocity of the current.
CorrectBy using cross multiplication formula;
Upstream Down stream Time
24 36 6
36 24 6.5Upstream speed of man = (24 × 24 – 36 × 36)/(24 × 6 – 36 × 6.5) = (-720)/(-90) = 8 km/hr
Downstream speed of man = (24 ×24-36 ×36)/(24 × 6.5-36 ×6) = (-720)/(-60) = 12 km/hr
∴ Speed of current = (12- 8)/2 = 2 km/hrIncorrectBy using cross multiplication formula;
Upstream Down stream Time
24 36 6
36 24 6.5Upstream speed of man = (24 × 24 – 36 × 36)/(24 × 6 – 36 × 6.5) = (-720)/(-90) = 8 km/hr
Downstream speed of man = (24 ×24-36 ×36)/(24 × 6.5-36 ×6) = (-720)/(-60) = 12 km/hr
∴ Speed of current = (12- 8)/2 = 2 km/hrUnattemptedBy using cross multiplication formula;
Upstream Down stream Time
24 36 6
36 24 6.5Upstream speed of man = (24 × 24 – 36 × 36)/(24 × 6 – 36 × 6.5) = (-720)/(-90) = 8 km/hr
Downstream speed of man = (24 ×24-36 ×36)/(24 × 6.5-36 ×6) = (-720)/(-60) = 12 km/hr
∴ Speed of current = (12- 8)/2 = 2 km/hr - Question 10 of 12
10. Question
1 pointsRamesh can row a certain distance downstream in 6 hours and return the same distance in 9 hours. If the stream flows at the rate of 3km per hour find the speed of Ramesh in still water.
CorrectRamesh’s speed in still water = (3 (9 + 6))/(9 – 6) = 15 km/hr.
IncorrectRamesh’s speed in still water = (3 (9 + 6))/(9 – 6) = 15 km/hr.
UnattemptedRamesh’s speed in still water = (3 (9 + 6))/(9 – 6) = 15 km/hr.
- Question 11 of 12
11. Question
1 pointsIf a man’s rate with the current is 12km/hr and the rate of the current is 1.5 km/hr, then the man’s rate against the current is ___?
CorrectMan’s rate against current = Man’s rate with current – 2 × rate of current
= 12 – 2 × 1.5
= 9 km/hrIncorrectMan’s rate against current = Man’s rate with current – 2 × rate of current
= 12 – 2 × 1.5
= 9 km/hrUnattemptedMan’s rate against current = Man’s rate with current – 2 × rate of current
= 12 – 2 × 1.5
= 9 km/hr - Question 12 of 12
12. Question
1 pointsRavish drive an electric boat that can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by Ravish’s boat to go 68 km downstream.
CorrectSpeed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = 68/17 hrs = 4 hours.IncorrectSpeed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = 68/17 hrs = 4 hours.UnattemptedSpeed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = 68/17 hrs = 4 hours.
