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Quiz Description :
Name: Boats and Stream objective Test – 2
Subject: Aptitude
Topic: Boats and Stream
Questions: 12
Time Allowed: 20 minutes
Important for: SSC ( CGL, CHSL, GD, MTS, JE), IBPS, SBI, RBI ( Clerk, PO, SO, Assistant), IIT JEE, AIPMT, Aptitude test and other competitions.
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 Review
 Question 1 of 12
1. Question
1 pointsA man can row upstream at 10 km/hr and downstreams at 16 km/hr. What is the rate of the current.
CorrectRate of current = 1/2(16 10) = 3 km/hr
IncorrectRate of current = 1/2(16 10) = 3 km/hr
UnattemptedRate of current = 1/2(16 10) = 3 km/hr
 Question 2 of 12
2. Question
1 pointsA man swings downstream 30 km and upstream 18 km, taking 3 hours catch time. What is the velocity of current?
CorrectMan’s rate downstream = 30/3 km/hr = 10 km/hr
Man’s rate upstream = 18/3 km/hr = 6 km/hr
∴ Velocity of stream (current) = ((10 – 6))/2 = 2 km/hrIncorrectMan’s rate downstream = 30/3 km/hr = 10 km/hr
Man’s rate upstream = 18/3 km/hr = 6 km/hr
∴ Velocity of stream (current) = ((10 – 6))/2 = 2 km/hrUnattemptedMan’s rate downstream = 30/3 km/hr = 10 km/hr
Man’s rate upstream = 18/3 km/hr = 6 km/hr
∴ Velocity of stream (current) = ((10 – 6))/2 = 2 km/hr  Question 3 of 12
3. Question
1 pointsA man can row 6km/hr in still water. It takes him twice as long to row up as to row down the river. What is the rate of the stream?
CorrectLet rate of stream = x km/hr
Then, 6 + x = 2 (6 – x)
or, 3x = 6
∴ x= 6/3 = 2 km/hrIncorrectLet rate of stream = x km/hr
Then, 6 + x = 2 (6 – x)
or, 3x = 6
∴ x= 6/3 = 2 km/hrUnattemptedLet rate of stream = x km/hr
Then, 6 + x = 2 (6 – x)
or, 3x = 6
∴ x= 6/3 = 2 km/hr  Question 4 of 12
4. Question
1 pointsA man can row 6 km/hr in still water. When the river is running at 1.2 km/hr, it takes him 1 hour to row to a place and back. How far is the place?
CorrectRequired distance = ([1 ×(6^{2} – 1.2^{2})])/((2 × 6)) = (36 1.44)/12 = 3 – 0.12 = 2.88 km.
IncorrectRequired distance = ([1 ×(6^{2} – 1.2^{2})])/((2 × 6)) = (36 1.44)/12 = 3 – 0.12 = 2.88 km.
UnattemptedRequired distance = ([1 ×(6^{2} – 1.2^{2})])/((2 × 6)) = (36 1.44)/12 = 3 – 0.12 = 2.88 km.
 Question 5 of 12
5. Question
1 pointsIn a stream running at 2km/hr, a motorboat goes 10km upstream and back again to the starting point in 55 minutes. What is the speed of the motorboat in still water?
Correct10= 55/60×(x^{2} – 2^{2})/2x
or, 1200 x = 55 (x^{2} – 4)
or, 11 x^{2} – 240 x – 44 = 0
∴ (x – 22)(11 x + 2) = 0
So, x = 22 km/hr (neglecting the –ve value)Incorrect10= 55/60×(x^{2} – 2^{2})/2x
or, 1200 x = 55 (x^{2} – 4)
or, 11 x^{2} – 240 x – 44 = 0
∴ (x – 22)(11 x + 2) = 0
So, x = 22 km/hr (neglecting the –ve value)Unattempted10= 55/60×(x^{2} – 2^{2})/2x
or, 1200 x = 55 (x^{2} – 4)
or, 11 x^{2} – 240 x – 44 = 0
∴ (x – 22)(11 x + 2) = 0
So, x = 22 km/hr (neglecting the –ve value)  Question 6 of 12
6. Question
1 pointsA man can row 30km upstream and 44 km downstream in 10 hours. Also, he can row 40 km upstream and 55km downstream in 13 hours. What is the rate of the current and the speed of the man in still water?
CorrectBy using cross multiplication formula;
Upstream Down stream Time
30 44 10
40 55 13Upstream speed of man = (30 × 55 – 40 × 44)/(55 × 10 – 44 × 13) = (110)/(22) = 5 km/hr
Downstream speed of man = (30 ×5540 ×44)/(30 ×1340 ×10) = (110)/(10) = 11 km/hr
∴ Speed of man = (5 + 11)/2 = 8 km/hr
and speed of stream = (11 – 5)/2 = 3 km/hr.IncorrectBy using cross multiplication formula;
Upstream Down stream Time
30 44 10
40 55 13Upstream speed of man = (30 × 55 – 40 × 44)/(55 × 10 – 44 × 13) = (110)/(22) = 5 km/hr
Downstream speed of man = (30 ×5540 ×44)/(30 ×1340 ×10) = (110)/(10) = 11 km/hr
∴ Speed of man = (5 + 11)/2 = 8 km/hr
and speed of stream = (11 – 5)/2 = 3 km/hr.UnattemptedBy using cross multiplication formula;
Upstream Down stream Time
30 44 10
40 55 13Upstream speed of man = (30 × 55 – 40 × 44)/(55 × 10 – 44 × 13) = (110)/(22) = 5 km/hr
Downstream speed of man = (30 ×5540 ×44)/(30 ×1340 ×10) = (110)/(10) = 11 km/hr
∴ Speed of man = (5 + 11)/2 = 8 km/hr
and speed of stream = (11 – 5)/2 = 3 km/hr.  Question 7 of 12
7. Question
1 pointsA man can row 15km/hr in still water. It takes him twice as long to row up as to row down the river. What is the rate of the stream?
CorrectLet rate of stream = x km/hr
Then, 15 + x = 2 (15 – x)
or, 3x = 15
∴ x= 15/3 = 5 km/hrIncorrectLet rate of stream = x km/hr
Then, 15 + x = 2 (15 – x)
or, 3x = 15
∴ x= 15/3 = 5 km/hrUnattemptedLet rate of stream = x km/hr
Then, 15 + x = 2 (15 – x)
or, 3x = 15
∴ x= 15/3 = 5 km/hr  Question 8 of 12
8. Question
1 pointsA man can row 9 km/hr in still water. When the river is running at 2.5 km/hr, it takes him 3 hour to row to a place and back. How far is the place?
CorrectRequired distance = ([3 ×(9^{2} – 2.5^{2})])/((2 × 9)) = (3 × (81 6.25))/18 = 224.25/18 = 12.46 km.
IncorrectRequired distance = ([3 ×(9^{2} – 2.5^{2})])/((2 × 9)) = (3 × (81 6.25))/18 = 224.25/18 = 12.46 km.
UnattemptedRequired distance = ([3 ×(9^{2} – 2.5^{2})])/((2 × 9)) = (3 × (81 6.25))/18 = 224.25/18 = 12.46 km.
 Question 9 of 12
9. Question
1 pointsA boat covers 24 km upstream and 36 km downstream in 6 hours, while it covers 36 km upstream and 24 km downstream in 6.5 hours. Find the velocity of the current.
CorrectBy using cross multiplication formula;
Upstream Down stream Time
24 36 6
36 24 6.5Upstream speed of man = (24 × 24 – 36 × 36)/(24 × 6 – 36 × 6.5) = (720)/(90) = 8 km/hr
Downstream speed of man = (24 ×2436 ×36)/(24 × 6.536 ×6) = (720)/(60) = 12 km/hr
∴ Speed of current = (12 8)/2 = 2 km/hrIncorrectBy using cross multiplication formula;
Upstream Down stream Time
24 36 6
36 24 6.5Upstream speed of man = (24 × 24 – 36 × 36)/(24 × 6 – 36 × 6.5) = (720)/(90) = 8 km/hr
Downstream speed of man = (24 ×2436 ×36)/(24 × 6.536 ×6) = (720)/(60) = 12 km/hr
∴ Speed of current = (12 8)/2 = 2 km/hrUnattemptedBy using cross multiplication formula;
Upstream Down stream Time
24 36 6
36 24 6.5Upstream speed of man = (24 × 24 – 36 × 36)/(24 × 6 – 36 × 6.5) = (720)/(90) = 8 km/hr
Downstream speed of man = (24 ×2436 ×36)/(24 × 6.536 ×6) = (720)/(60) = 12 km/hr
∴ Speed of current = (12 8)/2 = 2 km/hr  Question 10 of 12
10. Question
1 pointsRamesh can row a certain distance downstream in 6 hours and return the same distance in 9 hours. If the stream flows at the rate of 3km per hour find the speed of Ramesh in still water.
CorrectRamesh’s speed in still water = (3 (9 + 6))/(9 – 6) = 15 km/hr.
IncorrectRamesh’s speed in still water = (3 (9 + 6))/(9 – 6) = 15 km/hr.
UnattemptedRamesh’s speed in still water = (3 (9 + 6))/(9 – 6) = 15 km/hr.
 Question 11 of 12
11. Question
1 pointsIf a man’s rate with the current is 12km/hr and the rate of the current is 1.5 km/hr, then the man’s rate against the current is ___?
CorrectMan’s rate against current = Man’s rate with current – 2 × rate of current
= 12 – 2 × 1.5
= 9 km/hrIncorrectMan’s rate against current = Man’s rate with current – 2 × rate of current
= 12 – 2 × 1.5
= 9 km/hrUnattemptedMan’s rate against current = Man’s rate with current – 2 × rate of current
= 12 – 2 × 1.5
= 9 km/hr  Question 12 of 12
12. Question
1 pointsRavish drive an electric boat that can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by Ravish’s boat to go 68 km downstream.
CorrectSpeed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = 68/17 hrs = 4 hours.IncorrectSpeed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = 68/17 hrs = 4 hours.UnattemptedSpeed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = 68/17 hrs = 4 hours.