0 of 11 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 11
Information
Name:Boats and Stream Exercise – 3
Subject: Numerical Aptitude ( संख्यात्मक अभियोगिता)
Topic: Boats & Stream – 1
Questions: 11 Objective Type Questions
Time Allowed: 30 Minutes
Language: English
Important for: Police Exam, SSC ( CGL, CHSL, GD etc), State PCS, UPSC, Railway, IBPS Clerk, IBPS RRB, SBI Clerk, Engineering Entrance exam, समूह ग आदि 
You have already completed the Test before. Hence you can not start it again.
Test is loading...
You must sign in or sign up to start the Test.
You have to finish following quiz, to start this Test:
Congratulations!!!" Boats and Stream Exercise  3 "
0 of 11 questions answered correctly
Your time:
Time has elapsed
Your Final Score is : 0
You have attempted : 0
Number of Correct Questions : 0 and scored 0
Number of Incorrect Questions : 0 and Negative marks 0
Average score  
Your score 

Not categorized
You have attempted: 0
Number of Correct Questions: 0 and scored 0
Number of Incorrect Questions: 0 and Negative marks 0
Share this test with your friends on Facebook, WhatsApp, Twitter, etc.
Pos.  Name  Entered on  Points  Result 

Table is loading  
No data available  
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 11
 Answered
 Review
 Question 1 of 11
1. Question
1 pointsA man rows downstream 32 km and 14 upstream. If he takes 6 hours to cover each distance, then the velocity (in kmph) of the current is:
CorrectRate downstream = \(\left ( \frac{32}{6}\right )
Rate upstream = \left ( \frac{14}{6} \right ) kmph.\)
Velocity of current = \(\frac{1}{2}\left ( \frac{32}{6}\frac{14}{6} \right )kmph
= \frac{3}{2}kmph = 1.5 kmph.\)IncorrectRate downstream = \(\left ( \frac{32}{6}\right )
Rate upstream = \left ( \frac{14}{6} \right ) kmph.\)
Velocity of current = \(\frac{1}{2}\left ( \frac{32}{6}\frac{14}{6} \right )kmph
= \frac{3}{2}kmph = 1.5 kmph.\)UnattemptedRate downstream = \(\left ( \frac{32}{6}\right )
Rate upstream = \left ( \frac{14}{6} \right ) kmph.\)
Velocity of current = \(\frac{1}{2}\left ( \frac{32}{6}\frac{14}{6} \right )kmph
= \frac{3}{2}kmph = 1.5 kmph.\)  Question 2 of 11
2. Question
1 pointsIn one hour, a boat in km/hr) is goes 11 km along the stream and 5 km against the stream. The speed of the boat in still water
CorrectSpeed in still water = \(\frac{1}{2}\left ( 11+5 \right )kmph = 8 kmph.\)
IncorrectSpeed in still water = \(\frac{1}{2}\left ( 11+5 \right )kmph = 8 kmph.\)
UnattemptedSpeed in still water = \(\frac{1}{2}\left ( 11+5 \right )kmph = 8 kmph.\)
 Question 3 of 11
3. Question
1 pointsA boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream, it takes 4 hours. What is the speed of the boat in still water?
CorrectRate downstream = \(\left ( \frac{16}{2} \right )kmph = 8 kmph; Rate upstream = \frac{16}{4}kmph = 4 kmph.\)
Speed in still water = \(\frac{1}{2}(8+4) kmph = 6 kmph.\)IncorrectRate downstream = \(\left ( \frac{16}{2} \right )kmph = 8 kmph; Rate upstream = \frac{16}{4}kmph = 4 kmph.\)
Speed in still water = \(\frac{1}{2}(8+4) kmph = 6 kmph.\)UnattemptedRate downstream = \(\left ( \frac{16}{2} \right )kmph = 8 kmph; Rate upstream = \frac{16}{4}kmph = 4 kmph.\)
Speed in still water = \(\frac{1}{2}(8+4) kmph = 6 kmph.\)  Question 4 of 11
4. Question
1 pointsA man takes twice as long to row a distance against the stream as to row the same distance in favor of the stream. The ratio of the speed of the boat (in still water) and the stream is:
CorrectLet man’s rate upstream be x kmph. Then, his rate downstream = 2x kmph.
(Speed in still water) : (Speed of stream) = \(\left ( \frac{2x+x}{2} \right ) : \left (\frac{2xx}{2} \right ) = \frac{3x}{2} : \frac{x}{2} = 3 : 1\)IncorrectLet man’s rate upstream be x kmph. Then, his rate downstream = 2x kmph.
(Speed in still water) : (Speed of stream) = \(\left ( \frac{2x+x}{2} \right ) : \left (\frac{2xx}{2} \right ) = \frac{3x}{2} : \frac{x}{2} = 3 : 1\)UnattemptedLet man’s rate upstream be x kmph. Then, his rate downstream = 2x kmph.
(Speed in still water) : (Speed of stream) = \(\left ( \frac{2x+x}{2} \right ) : \left (\frac{2xx}{2} \right ) = \frac{3x}{2} : \frac{x}{2} = 3 : 1\)  Question 5 of 11
5. Question
1 pointsIf a man rows at the rate of 5 kmph is still water and his rate against the current is 3.5 kmph, then the man’s rate along the current is:
CorrectLet the rate along the current be x kmph. Then \(\frac{1}{2}(x+3.5)=5 or x = 6.5 kmph.\)
IncorrectLet the rate along the current be x kmph. Then \(\frac{1}{2}(x+3.5)=5 or x = 6.5 kmph.\)
UnattemptedLet the rate along the current be x kmph. Then \(\frac{1}{2}(x+3.5)=5 or x = 6.5 kmph.\)
 Question 6 of 11
6. Question
1 pointsA boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
CorrectSpeed downstream = (13+4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = \(\left ( \frac{68}{17} \right )hrs = 4 hrs.\)IncorrectSpeed downstream = (13+4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = \(\left ( \frac{68}{17} \right )hrs = 4 hrs.\)UnattemptedSpeed downstream = (13+4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream = \(\left ( \frac{68}{17} \right )hrs = 4 hrs.\)  Question 7 of 11
7. Question
1 pointsSpeed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is:
CorrectSpeed upstream = 7.5 kmph; Speed downstream = 10.5 kmph.
Total time taken = \(\left ( \frac{105}{7.5}+\frac{105}{10.5} \right ) hours = 24 hours\)IncorrectSpeed upstream = 7.5 kmph; Speed downstream = 10.5 kmph.
Total time taken = \(\left ( \frac{105}{7.5}+\frac{105}{10.5} \right ) hours = 24 hours\)UnattemptedSpeed upstream = 7.5 kmph; Speed downstream = 10.5 kmph.
Total time taken = \(\left ( \frac{105}{7.5}+\frac{105}{10.5} \right ) hours = 24 hours\)  Question 8 of 11
8. Question
1 pointsThe speed of a boat in still water is 15 km/hr and the rate of current is 3 km/hr. The distance traveled downstream in 12 minutes is:
CorrectSpeed downstream = (15+3) kmph = 18 kmph
Distance traveled = \(\left ( 18\times\frac{12}{60} \right )km = 3.6 km\)IncorrectSpeed downstream = (15+3) kmph = 18 kmph
Distance traveled = \(\left ( 18\times\frac{12}{60} \right )km = 3.6 km\)UnattemptedSpeed downstream = (15+3) kmph = 18 kmph
Distance traveled = \(\left ( 18\times\frac{12}{60} \right )km = 3.6 km\)  Question 9 of 11
9. Question
1 pointsA man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?
CorrectSpeed downstream = (5+1) kmph = 6 kmph;
Speed upstream = (51) kmph = 4 kmph.
Let the required distance be x km.
Then, \(\frac{x}{6}+\frac{x}{4}= 1\)
\(\Rightarrow 2x + 3x = 12 \)
\(\Rightarrow 5x = 12 \)
\(\Rightarrow x =2.4 km\)IncorrectSpeed downstream = (5+1) kmph = 6 kmph;
Speed upstream = (51) kmph = 4 kmph.
Let the required distance be x km.
Then, \(\frac{x}{6}+\frac{x}{4}= 1\)
\(\Rightarrow 2x + 3x = 12 \)
\(\Rightarrow 5x = 12 \)
\(\Rightarrow x =2.4 km\)UnattemptedSpeed downstream = (5+1) kmph = 6 kmph;
Speed upstream = (51) kmph = 4 kmph.
Let the required distance be x km.
Then, \(\frac{x}{6}+\frac{x}{4}= 1\)
\(\Rightarrow 2x + 3x = 12 \)
\(\Rightarrow 5x = 12 \)
\(\Rightarrow x =2.4 km\)  Question 10 of 11
10. Question
1 pointsA boat covers a certain distance downstream in 1 hour, while it come back in \(1\frac{1}{2}\) hours. If the speed of the stream be 3 kmph, what is the still water?
CorrectLet the speed of the boat is still water be x kmph. Then,
Speed downstream = (x+3) kmph,
Speed upstream = (x3) kmph.
\((x+3)\times1=(x3)\times\frac{3}{2}\)
\(\Leftrightarrow 2x + 6 = 3x – 9\)
\(\Leftrightarrow x= 15 kmph.\)IncorrectLet the speed of the boat is still water be x kmph. Then,
Speed downstream = (x+3) kmph,
Speed upstream = (x3) kmph.
\((x+3)\times1=(x3)\times\frac{3}{2}\)
\(\Leftrightarrow 2x + 6 = 3x – 9\)
\(\Leftrightarrow x= 15 kmph.\)UnattemptedLet the speed of the boat is still water be x kmph. Then,
Speed downstream = (x+3) kmph,
Speed upstream = (x3) kmph.
\((x+3)\times1=(x3)\times\frac{3}{2}\)
\(\Leftrightarrow 2x + 6 = 3x – 9\)
\(\Leftrightarrow x= 15 kmph.\)  Question 11 of 11
11. Question
1 pointsA man can row threequarters of a kilometer against the in \(11\frac{1}{4}\) minutes and can row the same distance in \(7\frac{1}{2}\) minutes in downstream. The speed (in km/hr) of the man in still water is:
CorrectRate upstream = \(\left ( \frac{750}{675} \right )m/sec=\frac{10}{9}m/sec\)
Rate downstream = \(\left ( \frac{750}{450} \right )m/sec=\frac{5}{3}m/sec\)
Rate in still water = \(\frac{1}{2}\left ( \frac{10}{9}+\frac{5}{3} \right ) \)m/sec
= \(\frac{25}{18}\)m/sec
=\(\left ( \frac{25}{18} \times\frac{18}{5}\right )km/hr = 5 km/hr.\)IncorrectRate upstream = \(\left ( \frac{750}{675} \right )m/sec=\frac{10}{9}m/sec\)
Rate downstream = \(\left ( \frac{750}{450} \right )m/sec=\frac{5}{3}m/sec\)
Rate in still water = \(\frac{1}{2}\left ( \frac{10}{9}+\frac{5}{3} \right ) \)m/sec
= \(\frac{25}{18}\)m/sec
=\(\left ( \frac{25}{18} \times\frac{18}{5}\right )km/hr = 5 km/hr.\)UnattemptedRate upstream = \(\left ( \frac{750}{675} \right )m/sec=\frac{10}{9}m/sec\)
Rate downstream = \(\left ( \frac{750}{450} \right )m/sec=\frac{5}{3}m/sec\)
Rate in still water = \(\frac{1}{2}\left ( \frac{10}{9}+\frac{5}{3} \right ) \)m/sec
= \(\frac{25}{18}\)m/sec
=\(\left ( \frac{25}{18} \times\frac{18}{5}\right )km/hr = 5 km/hr.\)