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**Quiz Description** :

**Name: **Wave Motion and Sound mcqs : Physics quiz

**Subject: **Physics

**Topic: **Wave Motion and Sound

**Questions: **9

**Time Allowed: **15 minutes

**Important for: **11th & 12th school students, Engineering & Medical entrance exams etc.

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- Question 1 of 9
##### 1. Question

1 pointsWhich of the following is different from others?

CorrectWe know that the velocity, wavelength and frequency are related with each other as v = ν × h, whereas amplitude is not related to any one of these.

Therefore amplitude is different from the remaining three.IncorrectWe know that the velocity, wavelength and frequency are related with each other as v = ν × h, whereas amplitude is not related to any one of these.

Therefore amplitude is different from the remaining three. - Question 2 of 9
##### 2. Question

1 pointsWith the propagation of a longitudinal wave through a material medium, which of the following quantity is transmitted in the direction of its propagation?

CorrectWe know that with the propagation of a longitudinal wave through a material medium, only energy is transmitted in the direction of its propagation.

IncorrectWe know that with the propagation of a longitudinal wave through a material medium, only energy is transmitted in the direction of its propagation.

- Question 3 of 9
##### 3. Question

1 pointsThe waves produced by a motorboat, sailing in water, are

CorrectWe know that waves produced by a motorboat, sailing in water, are transverse on the surface and longitudinal inside the water.

IncorrectWe know that waves produced by a motorboat, sailing in water, are transverse on the surface and longitudinal inside the water.

- Question 4 of 9
##### 4. Question

1 pointsWhich of the following is an example of transverse wave?

CorrectWe know that a transverse wave is a wave, in which particles of the medium vibrate about their mean position in a direction at right angles to the direction of propagation of the wave. Thus vibration of the string is the example of transverse wave.

IncorrectWe know that a transverse wave is a wave, in which particles of the medium vibrate about their mean position in a direction at right angles to the direction of propagation of the wave. Thus vibration of the string is the example of transverse wave.

- Question 5 of 9
##### 5. Question

1 pointsTwo sound waves having a phase difference of 60° have path difference of

CorrectWe have, phase difference (Δϕ) = 60° = π/3 rad

We know that path difference = (Δx) = (λ/2π)×Δϕ = (λ/2π) × π/3 = π/6IncorrectWe have, phase difference (Δϕ) = 60° = π/3 rad

We know that path difference = (Δx) = (λ/2π)×Δϕ = (λ/2π) × π/3 = π/6 - Question 6 of 9
##### 6. Question

1 pointsTwo waves are approaching each other with a velocity of 20 m-s

^{-1}and frequency ν. The distance between two consecutive nodes isCorrectWe have, velocity of waves (v) = 20 m-s

^{-1}and frequency of waves = ν.

We know that distance between two consecutive nodes = λ/2 = v/(2ν) = 20/ 2ν = 10/νIncorrectWe have, velocity of waves (v) = 20 m-s

^{-1}and frequency of waves = ν.

We know that distance between two consecutive nodes = λ/2 = v/(2ν) = 20/ 2ν = 10/ν - Question 7 of 9
##### 7. Question

1 pointsIf the phase difference between two points is 60° on a wave velocity of 360 m-s

^{-1}and frequency 500 Hz, then path difference between the two points isCorrectWe have, phase difference between two points (Δϕ) = 60° = π/3 rad;

Velocity of wave (v) = 360 m-s^{-1}and frequency of wave (ν) = 500 Hz

We know that wavelength of a wave (λ) = v/ν = 360/500 = 0.72m

Therefore path difference between two points (Δx) = [λ/(2π)]×Δϕ = [0.72/2π]×[π/3] = 0.12mIncorrectWe have, phase difference between two points (Δϕ) = 60° = π/3 rad;

Velocity of wave (v) = 360 m-s^{-1}and frequency of wave (ν) = 500 Hz

We know that wavelength of a wave (λ) = v/ν = 360/500 = 0.72m

Therefore path difference between two points (Δx) = [λ/(2π)]×Δϕ = [0.72/2π]×[π/3] = 0.12m - Question 8 of 9
##### 8. Question

1 pointsThe displacement of a wave is given by the equation:

_{y=10 sin[(2πt/30)+α].}If the displacement is 5cm at t=0, then angle described by the wave at t=7.5s will be

CorrectWe have, equation of wave:

_{y=10 sin[(2πt/30)+α]}; Displacement (y) = 5cm; Initial time (t_{1}) = 0 and Final time (t_{2}) = 7.5s

We know that displacement of wave at t = 0, 5 = 10 sin α or sin α = 1/2 or α = π/6

Therefore angle described by the wave at t=7.5s, (θ) = [(2πt)/30]+α = 2π/3 rad.IncorrectWe have, equation of wave:

_{y=10 sin[(2πt/30)+α]}; Displacement (y) = 5cm; Initial time (t_{1}) = 0 and Final time (t_{2}) = 7.5s

We know that displacement of wave at t = 0, 5 = 10 sin α or sin α = 1/2 or α = π/6

Therefore angle described by the wave at t=7.5s, (θ) = [(2πt)/30]+α = 2π/3 rad. - Question 9 of 9
##### 9. Question

1 pointsIn a function, A sings with certain frequency and B sings with a frequency of 1/8 of A. If energy remains the same and amplitude of A is ‘a’, then amplitude of B is

CorrectWe have, Frequecny of A(v

_{A}) = v; Frequency of B(v_{B}) = v/8 and amplitude of A(a_{A})=a.

We know that energy of a wave (E) = 1/2 mv^{2}= 1/2 m (a^{2}) = 1/2 ma^{2}(2πv)^{2 }∝ a^{2}v^{2}

Therefore; a_{B}= 8a_{A}= 8aIncorrectWe have, Frequecny of A(v

_{A}) = v; Frequency of B(v_{B}) = v/8 and amplitude of A(a_{A})=a.

We know that energy of a wave (E) = 1/2 mv^{2}= 1/2 m (a^{2}) = 1/2 ma^{2}(2πv)^{2 }∝ a^{2}v^{2}

Therefore; a_{B}= 8a_{A}= 8a