0 of 8 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
Information
Quiz Description :
Name: Order of magnitude : Physics Quiz
Subject: Physics
Topic: Order of magnitude
Questions: 8 MCQ
Time Allowed: 12 minutes
Important for: IIT JEE, UPSEE, WBJEE Engineering Entrance exams, AIPMT and other PMT entrance test, +2 school students and B. Sc. / M. Sc. College Students.
You have already completed the Test before. Hence you can not start it again.
Test is loading...
You must sign in or sign up to start the Test.
You have to finish following quiz, to start this Test:
Congratulations!!!" Order of magnitude "
0 of 8 questions answered correctly
Your time:
Time has elapsed
Your Final Score is : 0
You have attempted : 0
Number of Correct Questions : 0 and scored 0
Number of Incorrect Questions : 0 and Negative marks 0
Average score  
Your score 

Not categorized
You have attempted: 0
Number of Correct Questions: 0 and scored 0
Number of Incorrect Questions: 0 and Negative marks 0
It’s time to share this quiz with your friends on Facebook, Twitter, Google Plus, Whatsapp or LinkedIn…
Click on View Questions Button to check Correct and incorrect answers.
 1
 2
 3
 4
 5
 6
 7
 8
 Answered
 Review
 Question 1 of 8
1. Question
1 pointsA number is expressed as a × 10^{b}. The order of magnitude of this number is
CorrectGiven number = a × 10^{b}
We know that as the order of magnitude is the exponent of 10, therefore order of magnitude of the given number is ‘b’IncorrectGiven number = a × 10^{b}
We know that as the order of magnitude is the exponent of 10, therefore order of magnitude of the given number is ‘b’UnattemptedGiven number = a × 10^{b}
We know that as the order of magnitude is the exponent of 10, therefore order of magnitude of the given number is ‘b’  Question 2 of 8
2. Question
1 pointsIf electrostatic force between two charged particles is 4.3 × 10^{5} N, then the order of magnitude of this electrostatic force is
CorrectGiven that: The electrostatic force = 4.3 × 10^{5} N.
We know that as the order of magnitude is the exponent of 10, therefore order of magnitude of the electrostatic force is 5.IncorrectGiven that: The electrostatic force = 4.3 × 10^{5} N.
We know that as the order of magnitude is the exponent of 10, therefore order of magnitude of the electrostatic force is 5.UnattemptedGiven that: The electrostatic force = 4.3 × 10^{5} N.
We know that as the order of magnitude is the exponent of 10, therefore order of magnitude of the electrostatic force is 5.  Question 3 of 8
3. Question
1 pointsIf the diameter of sun is 1.39 × 10^{9} m, then diameter of sun is of the order of
CorrectGiven that the diameter of the sun = 1.39 × 10^{9} m.
We know that the round off number 1.39 is 1, because it is less than 5.
Therefore diameter of the sun is the order is 10^{9} m.IncorrectGiven that the diameter of the sun = 1.39 × 10^{9} m.
We know that the round off number 1.39 is 1, because it is less than 5.
Therefore diameter of the sun is the order is 10^{9} m.UnattemptedGiven that the diameter of the sun = 1.39 × 10^{9} m.
We know that the round off number 1.39 is 1, because it is less than 5.
Therefore diameter of the sun is the order is 10^{9} m.  Question 4 of 8
4. Question
1 pointsIf diameter of hydrogen atom is 1.06 × 10^{10} m, then its diameter is of the order of
CorrectGiven that the diameter of hydrogen atom = 1.06 × 10^{10} m.
We know that the round off number 1.06 is 1, because it is less than 5.
Therefore the diameter of hydrogen atom is of the order of 10^{10}.IncorrectGiven that the diameter of hydrogen atom = 1.06 × 10^{10} m.
We know that the round off number 1.06 is 1, because it is less than 5.
Therefore the diameter of hydrogen atom is of the order of 10^{10}.UnattemptedGiven that the diameter of hydrogen atom = 1.06 × 10^{10} m.
We know that the round off number 1.06 is 1, because it is less than 5.
Therefore the diameter of hydrogen atom is of the order of 10^{10}.  Question 5 of 8
5. Question
1 pointsIf mass of the electron is 9.11 × 10^{31} kg, then its mass is of the order of
CorrectGiven that the mass of electron = 9.11 Given that the mass of electron = 9.11 × 10^{31} kg.
We know that the round off number of 9.11 is 10, because it is greater than 5.
Therefore order of the given number is 10^{5}.IncorrectGiven that the mass of electron = 9.11 Given that the mass of electron = 9.11 × 10^{31} kg.
We know that the round off number of 9.11 is 10, because it is greater than 5.
Therefore order of the given number is 10^{5}.UnattemptedGiven that the mass of electron = 9.11 Given that the mass of electron = 9.11 × 10^{31} kg.
We know that the round off number of 9.11 is 10, because it is greater than 5.
Therefore order of the given number is 10^{5}.  Question 6 of 8
6. Question
1 pointsThe order of number 87962 is
CorrectGiven that the number is 87962. The given number may be written as 8.7962 × 10^{4}.
We know that the round off number 8.7962 is 9, because it is greater than 5.
Therefore order of the given number is 10^{5}.IncorrectGiven that the number is 87962. The given number may be written as 8.7962 × 10^{4}.
We know that the round off number 8.7962 is 9, because it is greater than 5.
Therefore order of the given number is 10^{5}.UnattemptedGiven that the number is 87962. The given number may be written as 8.7962 × 10^{4}.
We know that the round off number 8.7962 is 9, because it is greater than 5.
Therefore order of the given number is 10^{5}.  Question 7 of 8
7. Question
1 pointsThe order of (2)^{10} is approximately
CorrectThe given number is = (2)^{10}.
We know that (2)^{10} = 1024 = 1.024 × 10^{3}.
We also know that the round off 1.024 is 1, because it is less than 5.
Therefore order of the given number is 10^{3}.IncorrectThe given number is = (2)^{10}.
We know that (2)^{10} = 1024 = 1.024 × 10^{3}.
We also know that the round off 1.024 is 1, because it is less than 5.
Therefore order of the given number is 10^{3}.UnattemptedThe given number is = (2)^{10}.
We know that (2)^{10} = 1024 = 1.024 × 10^{3}.
We also know that the round off 1.024 is 1, because it is less than 5.
Therefore order of the given number is 10^{3}.  Question 8 of 8
8. Question
1 pointsTimetaken by sunlight to penetrate a window pan of 3 mm think is of the order of [Consider speed of light (c) = 3 × 10^{8} ms^{1}]
CorrectGiven that the thickness of window pan (x) = 3 mm = 3 × 10^{3} m and speed of light (c) = 3 × 10^{8} ms^{1}.
We know that time taken by sunlight to penetrate the window pan
(t) = x / c = 3 × 10^{3 }/ 3 × 10^{8} = 1 × 10^{11} s.
Therefore timetaken is of the order of 10^{11} s.IncorrectGiven that the thickness of window pan (x) = 3 mm = 3 × 10^{3} m and speed of light (c) = 3 × 10^{8} ms^{1}.
We know that time taken by sunlight to penetrate the window pan
(t) = x / c = 3 × 10^{3 }/ 3 × 10^{8} = 1 × 10^{11} s.
Therefore timetaken is of the order of 10^{11} s.UnattemptedGiven that the thickness of window pan (x) = 3 mm = 3 × 10^{3} m and speed of light (c) = 3 × 10^{8} ms^{1}.
We know that time taken by sunlight to penetrate the window pan
(t) = x / c = 3 × 10^{3 }/ 3 × 10^{8} = 1 × 10^{11} s.
Therefore timetaken is of the order of 10^{11} s.