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Quiz Description :
Name: Newton’s Law of Gravitational Force Objective Question answer test
Subject: Physics
Topic: Newton’s Law of Gravitational Force
Questions: 6 Objective Type
Time Allowed: 10 Minutes
Important for: IIT JEE, UPSEE, WBJEE Engineering Entrance exams, AIPMT and other PMT entrance test, +2 school students and B. Sc. / M. Sc. College Students.
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 Question 1 of 6
1. Question
1 pointsNewton’s law of gravitation is universal, because
CorrectWe know that Newton’s law of gravitation is universal, because it is always attractive and is not affected by any intervening medium.
It also acts on all masses at any distance.IncorrectWe know that Newton’s law of gravitation is universal, because it is always attractive and is not affected by any intervening medium.
It also acts on all masses at any distance.UnattemptedWe know that Newton’s law of gravitation is universal, because it is always attractive and is not affected by any intervening medium.
It also acts on all masses at any distance.  Question 2 of 6
2. Question
1 pointsThe force of gravitation is
CorrectWe know that the earth behaves as a huge magnet and has a tendency to attract all the objects due to gravitational force.
Therefore gravitational force is a conservative force.IncorrectWe know that the earth behaves as a huge magnet and has a tendency to attract all the objects due to gravitational force.
Therefore gravitational force is a conservative force.UnattemptedWe know that the earth behaves as a huge magnet and has a tendency to attract all the objects due to gravitational force.
Therefore gravitational force is a conservative force.  Question 3 of 6
3. Question
1 pointsThe mass of moon is about 1.3% of mass of the earth. Compared to the gravitational force the earth exerts on the moon, the gravitational forces the moon exerts on the earth
CorrectWe know that the Newton’s law of gravitation supports Newton’s third law of motion, i.e., to every action, there is always an equal and opposite reaction.
Therefore gravitational force which the earth exerts on the moon is the same as the gravitational force exerted by the moon on the earth. But it is opposite in direction.IncorrectWe know that the Newton’s law of gravitation supports Newton’s third law of motion, i.e., to every action, there is always an equal and opposite reaction.
Therefore gravitational force which the earth exerts on the moon is the same as the gravitational force exerted by the moon on the earth. But it is opposite in direction.UnattemptedWe know that the Newton’s law of gravitation supports Newton’s third law of motion, i.e., to every action, there is always an equal and opposite reaction.
Therefore gravitational force which the earth exerts on the moon is the same as the gravitational force exerted by the moon on the earth. But it is opposite in direction.  Question 4 of 6
4. Question
1 pointsIn a gravitational field, work done in transporting a mass from one point to another depends only upon
CorrectWe know that gravitational field is a conservative field, in which work done in transporting a mass from one point to another depends only upon the initial and final positions of the mass i.e., end positions and not on the path traversed.
IncorrectWe know that gravitational field is a conservative field, in which work done in transporting a mass from one point to another depends only upon the initial and final positions of the mass i.e., end positions and not on the path traversed.
UnattemptedWe know that gravitational field is a conservative field, in which work done in transporting a mass from one point to another depends only upon the initial and final positions of the mass i.e., end positions and not on the path traversed.
 Question 5 of 6
5. Question
1 pointsTwo spheres of masses m and M are situated in air and the gravitational force between them is F. The space around the masses is now filled with a liquid of specific gravity 3. The gravitational force will now be
CorrectWe have Mass of first sphere (m_{1}) = m; Mass of second sphere (m_{2}) = M; Initial gravitational force = F and specific gravity of liquid = 3.
We know from the Newton’s law of gravitation that the force of attraction between the two spheres = Gm_{1}m_{2}/ r^{2}.
Since the force of attraction between two bodies is independent of the nature of the intervening medium, therefore it will not change or in other words, it will be F.IncorrectWe have Mass of first sphere (m_{1}) = m; Mass of second sphere (m_{2}) = M; Initial gravitational force = F and specific gravity of liquid = 3.
We know from the Newton’s law of gravitation that the force of attraction between the two spheres = Gm_{1}m_{2}/ r^{2}.
Since the force of attraction between two bodies is independent of the nature of the intervening medium, therefore it will not change or in other words, it will be F.UnattemptedWe have Mass of first sphere (m_{1}) = m; Mass of second sphere (m_{2}) = M; Initial gravitational force = F and specific gravity of liquid = 3.
We know from the Newton’s law of gravitation that the force of attraction between the two spheres = Gm_{1}m_{2}/ r^{2}.
Since the force of attraction between two bodies is independent of the nature of the intervening medium, therefore it will not change or in other words, it will be F.  Question 6 of 6
6. Question
1 pointsIf the distance between the sun and the earth is increased by three times, then force of attraction between them will
CorrectWe have that final distance between sun and the earth (r_{2}) = 3r_{1} … (where r_{1} is initial distance between the sun and earth).
We know from the Newton’s law of gravitation that the force of attraction between sun and earth (F) = Gm_{s}m_{e}/r^{2} ∝ 1/r^{2}
Therefore F_{1}/F_{2} = (r_{2} / r_{1})^{2} = (3 r_{1} / r_{1})^{2} = 9 or F_{2} = F_{1}/9.
Thus decrease in force of attraction = F_{1} – F_{2} = F_{1} – F_{1}/9 = (8/9)F_{1} = 89%IncorrectWe have that final distance between sun and the earth (r_{2}) = 3r_{1} … (where r_{1} is initial distance between the sun and earth).
We know from the Newton’s law of gravitation that the force of attraction between sun and earth (F) = Gm_{s}m_{e}/r^{2} ∝ 1/r^{2}
Therefore F_{1}/F_{2} = (r_{2} / r_{1})^{2} = (3 r_{1} / r_{1})^{2} = 9 or F_{2} = F_{1}/9.
Thus decrease in force of attraction = F_{1} – F_{2} = F_{1} – F_{1}/9 = (8/9)F_{1} = 89%UnattemptedWe have that final distance between sun and the earth (r_{2}) = 3r_{1} … (where r_{1} is initial distance between the sun and earth).
We know from the Newton’s law of gravitation that the force of attraction between sun and earth (F) = Gm_{s}m_{e}/r^{2} ∝ 1/r^{2}
Therefore F_{1}/F_{2} = (r_{2} / r_{1})^{2} = (3 r_{1} / r_{1})^{2} = 9 or F_{2} = F_{1}/9.
Thus decrease in force of attraction = F_{1} – F_{2} = F_{1} – F_{1}/9 = (8/9)F_{1} = 89%