0 of 12 questions completed

Questions:

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12

#### Information

**Name: **Time and Distance mcq quiz – Level 2

**Subject: **Quantitative Aptitude

**Topic: **Speed Time and Distance

**Questions: **12 mcq type

**Time Allowed: **20 minutes

**Language:** English

**Difficulty Level**: 2 out of 10.

**Important for: **SSC CHSL, Amry, BSF, CRPF, Railways, Bank Clerk and 12th level competitions, 8th, 9th, 10th class school students.

You have already completed the Test before. Hence you can not start it again.

Test is loading...

You must sign in or sign up to start the Test.

You have to finish following quiz, to start this Test:

#### Congratulations!!!" Time and Distance mcq Quiz - Level 2 "

0 of 12 questions answered correctly

Your time:

Time has elapsed

Your Final Score is : 0

You have attempted : 0

Number of Correct Questions : 0 and scored 0

Number of Incorrect Questions : 0 and Negative marks 0

Average score | |

Your score |

- Not categorized

You have attempted: 0

Number of Correct Questions: 0 and scored 0

Number of Incorrect Questions: 0 and Negative marks 0

It’s time to share this quiz with your friends on

**Facebook**,**Twitter**,**Google Plus**,**Whatsapp**or**LinkedIn**…

Pos. | Name | Entered on | Points | Result |
---|---|---|---|---|

Table is loading | ||||

No data available | ||||

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12

- Answered
- Review

- Question 1 of 12
##### 1. Question

1 pointsBy walking 2/7 of his usual speed Ramesh is 15 minute late to his working timing. What is his usual time to cover the distance?

Correct**Explanation:**Usual Time = Late time / [(1 ÷ 2/7-1))]

= 15 / (7/2 – 1)

= (15 × 2) / 5

= 6 minutesIncorrect**Explanation:**Usual Time = Late time / [(1 ÷ 2/7-1))]

= 15 / (7/2 – 1)

= (15 × 2) / 5

= 6 minutes - Question 2 of 12
##### 2. Question

1 pointsBy running 4/3 of his usual speed, a person improves his timing by 10 minutes. What his usual time to cover the distance?

CorrectExplanation:

Usual Time = Improved time / [(1 – 1 ÷ 4/3))]

= 10 / (1 – 3/4)

= (10 × 4) / 1

= 40 minutesIncorrectExplanation:

Usual Time = Improved time / [(1 – 1 ÷ 4/3))]

= 10 / (1 – 3/4)

= (10 × 4) / 1

= 40 minutes - Question 3 of 12
##### 3. Question

1 pointsTwo man A and B start form a place P walking at 3 kilometer and 3.5 kilometer an hour respectively. How many kilometers will they be apart at the end of 3 hours of journey when they are walking in the opposite direction?

CorrectWhen they walk in opposite direction, they will be (3 + 3.5 = 6.5) kilometer apart in one hour.

∴ Required distance = 6.5 × 3 = 19.5 kilometerIncorrectWhen they walk in opposite direction, they will be (3 + 3.5 = 6.5) kilometer apart in one hour.

∴ Required distance = 6.5 × 3 = 19.5 kilometer - Question 4 of 12
##### 4. Question

1 pointsTwo man A and B start form a place P walking at 3 kilometer and 3.5 kilometer an hour respectively. How many kilometers will they be apart at the end of 3 hours of journey when they are walking in the same direction?

CorrectWhen they walk in same direction, they will be (|3 – 3.5| = 0.5) kilometer apart in one hour.

∴ Required distance = 0.5 × 3 = 1.5 kilometerIncorrectWhen they walk in same direction, they will be (|3 – 3.5| = 0.5) kilometer apart in one hour.

∴ Required distance = 0.5 × 3 = 1.5 kilometer - Question 5 of 12
##### 5. Question

1 pointsA train covers certain distance within 50 minutes, if it runs at a speed of 48 km/h on an average. The speed at which the train must run to reduce the time of the journey to 40 minutes will be?

CorrectTime to cover the distance by train (T) = 50/60 hours = 5/6 hours

Speed of the train to cover the distance (S) = 48 km/h

distance = S × T

= 48 × (5/6)

= 40km

New time to cover the distance = 40/60 hours

= 2/3 hours

New speed of the train (S) = D / T

= 40 / (2/3) km/h

= 60 km/hIncorrectTime to cover the distance by train (T) = 50/60 hours = 5/6 hours

Speed of the train to cover the distance (S) = 48 km/h

distance = S × T

= 48 × (5/6)

= 40km

New time to cover the distance = 40/60 hours

= 2/3 hours

New speed of the train (S) = D / T

= 40 / (2/3) km/h

= 60 km/h - Question 6 of 12
##### 6. Question

1 pointsBy running 13/11 of his usual speed a old lady is 18 minute improved to attend a doctor appointment. What is his usual time to cover the distance?

CorrectUsual Time = Improved time / [(1 – 1 ÷ 13/11))]

= 18 / (1 – 11/13)

= (18 × 13) / 2

= 117 minutes

= 1 hrs. 57 minutesIncorrectUsual Time = Improved time / [(1 – 1 ÷ 13/11))]

= 18 / (1 – 11/13)

= (18 × 13) / 2

= 117 minutes

= 1 hrs. 57 minutes - Question 7 of 12
##### 7. Question

1 pointsTwo man A and B start form a place P walking at 3 kilometer and 3.5 kilometer an hour respectively. What time will they take to be 16 kilometer apart when they are walking in the opposite direction?

CorrectWhen they walk in opposite direction, they will be (3 + 3.5 = 6.5) kilometer apart in one hour.

∴ Required time = 16 / 6.5 = 2.46 hoursIncorrectWhen they walk in opposite direction, they will be (3 + 3.5 = 6.5) kilometer apart in one hour.

∴ Required time = 16 / 6.5 = 2.46 hours - Question 8 of 12
##### 8. Question

1 pointsA train travelling 25 kilometer an hour leaves Delhi at 9 A.M. and another train travelling 35 kilometer an hour start at 2 P.M in the same direction. How many kilometers from Delhi will they be together?

CorrectMeeting point’s distance from the starting point =

[(Product of speed) / (Difference of speed)] × (Difference in time)

∴Required distance = [(25 × 35) / (35 – 25)] × (2 P.M – 9 A.M)

= (25 × 35 × 5) / 10

= 437.5 KilometerIncorrectMeeting point’s distance from the starting point =

[(Product of speed) / (Difference of speed)] × (Difference in time)

∴Required distance = [(25 × 35) / (35 – 25)] × (2 P.M – 9 A.M)

= (25 × 35 × 5) / 10

= 437.5 Kilometer - Question 9 of 12
##### 9. Question

1 pointsA motor car takes 50 seconds to travel 500 meters. What is its speed in km per hour?

CorrectSpeed in m/s = 500 / 50 = 10

∴ Speed in km/hr = 10 × (18/5) = 36 km/hr.IncorrectSpeed in m/s = 500 / 50 = 10

∴ Speed in km/hr = 10 × (18/5) = 36 km/hr. - Question 10 of 12
##### 10. Question

1 pointsWhat is the length of the bridge which a man riding 15 kilometer an hour can cross in 5 minutes?

CorrectDistance cover in 5 minutes = (15 / 60) × 5 = (15 / 12) = 5/4 kilometer = 1250 meters

IncorrectDistance cover in 5 minutes = (15 / 60) × 5 = (15 / 12) = 5/4 kilometer = 1250 meters

- Question 11 of 12
##### 11. Question

1 pointsI walk a certain distance and ride back and take 13/2 hour altogether. I could walk both ways in 31/4 hours. How long would it take me to ride both ways?

CorrectWalking + Riding = 13/2 hrs

Walking + Walking = 2 walking = 31/4 hrs

by solving these two equation we get;

2 Riding = 13 – 31 / 4 = 21 / 4 = 5 hrs. 15 min.IncorrectWalking + Riding = 13/2 hrs

Walking + Walking = 2 walking = 31/4 hrs

by solving these two equation we get;

2 Riding = 13 – 31 / 4 = 21 / 4 = 5 hrs. 15 min. - Question 12 of 12
##### 12. Question

1 pointsTwo persons M and N start form a place of P walking at 4.48 kilometer and 3.96 kilometer an hour respectively. How many kilometers will they be apart at the end of 5 hours of journey when they are walking in the same direction?

CorrectWhen they walk in same direction, they will be (|4.48 – 3.96| = 0.52) kilometer apart in one hour.

∴ Required time = 18 / 0.52 = 34.61 hoursIncorrectWhen they walk in same direction, they will be (|4.48 – 3.96| = 0.52) kilometer apart in one hour.

∴ Required time = 18 / 0.52 = 34.61 hours