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**Quiz Description** :

**Name: **Percentage Aptitude Question Answer Test – 2

**Subject: **Aptitude

**Topic: **Percentage Word Problem

**Questions: **12 Objective type

**Time Allowed: **20 minutes

**Important for: ** SSC CGL, CHSL, GD, SBI Clerk, IBPS PO / Clerk, LIC Insurance, Railways, school students of class 8th, 9th, 10th, 11th and 12th, B. Sc. (maths), IIT-JEE, AIPMT, Teaching entrance, Jobs written test of WIPRO, InfoSys, IBM, UHG, Tech- Mahindra, TCS, TCL and other center level and state level competitions.

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- Question 1 of 12
##### 1. Question

1 pointsThe population of a village has increased from 60,000 to 65,000. What is the increased percentage of the village?

CorrectIncrease in population = 65000 – 60000 = 5000

Percentage increase = 5000/60000×100= 25/3%IncorrectIncrease in population = 65000 – 60000 = 5000

Percentage increase = 5000/60000×100= 25/3% - Question 2 of 12
##### 2. Question

1 points. In an election of two candidates, the candidate who gets 41% is rejected by a majority of 2412 votes. Find the total number of votes polled.

CorrectPercentage difference between candidate polled votes = (59% – 41%) = 18 %

As per the question;

candidate rejected by 18% of majority = 2412 votes

∴100% = 2412/18×100 = 13400 votesIncorrectPercentage difference between candidate polled votes = (59% – 41%) = 18 %

As per the question;

candidate rejected by 18% of majority = 2412 votes

∴100% = 2412/18×100 = 13400 votes - Question 3 of 12
##### 3. Question

1 pointsWyatt’s salary is increased from Rs. 1500 to Rs. 1830. Find the increase percentage.

CorrectIncrease in salary = Rs 1830 – Rs. 1500 = Rs. 330

Percentage in salary = 330/1500×100

= 22%IncorrectIncrease in salary = Rs 1830 – Rs. 1500 = Rs. 330

Percentage in salary = 330/1500×100

= 22% - Question 4 of 12
##### 4. Question

1 pointsThe population of a town has increased from 5000 to 13000. What is the increased percentage of the town?

CorrectIncrease in population = 13000 – 5000 =8000

Percentage increase = (8000/5000)×100= 800/5=160%IncorrectIncrease in population = 13000 – 5000 =8000

Percentage increase = (8000/5000)×100= 800/5=160% - Question 5 of 12
##### 5. Question

1 pointsIf 10 liters of water is evaporated on boiling from 15 liters of sugar solution containing 10% sugar, find the percentage of sugar in the remaining solution.

Correct% of sugar in the original solution = 10% of 15 liters = 10/100×15 = 1.5%

After evaporation of 10 liters of water, the quantity of the remaining solution = 15 – 10 = 5 liters

∴The required percentage of sugar = 1.5/5×100% = 150/5 = 30%Incorrect% of sugar in the original solution = 10% of 15 liters = 10/100×15 = 1.5%

After evaporation of 10 liters of water, the quantity of the remaining solution = 15 – 10 = 5 liters

∴The required percentage of sugar = 1.5/5×100% = 150/5 = 30% - Question 6 of 12
##### 6. Question

1 pointsOne type of liquid contains 25% of milk, the other contains 30% of milk. A cane of filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of milk in the new mixture.

CorrectIncorrect - Question 7 of 12
##### 7. Question

1 pointsDue to fall in manpower, the production in a factory decrease by 25%. By what percent should the working hour be increased to restore the original production?

CorrectLet us consider the manpower = 100 units and

Working hours = 100 units

Suppose working hours increase by x%.

Then, (100- 25) (100 + x) = 100 × 100

or 100+x= 400/3

∴ x= 400/3IncorrectLet us consider the manpower = 100 units and

Working hours = 100 units

Suppose working hours increase by x%.

Then, (100- 25) (100 + x) = 100 × 100

or 100+x= 400/3

∴ x= 400/3 - Question 8 of 12
##### 8. Question

1 pointsA man had some eggs. Out of them 4% were thrown away as they had become rotten, 80% of the remaining eggs were sold and now he was left with only 96 eggs. How many eggs had he in the beginning?

Correct**Method 1:**Let he had 100 eggs in all.

The number of rotten eggs = 4% of 100 = 4

∴ Remaining eggs = 100 – 4 = 96

The eggs sold = 80% of 96

= 80×96/100= 384/5

∴ Remaining eggs = 96- 384/5 = 96/5

If 96/5 eggs are left, then eggs**Short Method 2:**Total eggs = (A×100×100)/(100-x)(100-y)

= (96×100×100)/(100-4)(100-80) =510.63≈511Incorrect**Method 1:**Let he had 100 eggs in all.

The number of rotten eggs = 4% of 100 = 4

∴ Remaining eggs = 100 – 4 = 96

The eggs sold = 80% of 96

= 80×96/100= 384/5

∴ Remaining eggs = 96- 384/5 = 96/5

If 96/5 eggs are left, then eggs**Short Method 2:**Total eggs = (A×100×100)/(100-x)(100-y)

= (96×100×100)/(100-4)(100-80) =510.63≈511 - Question 9 of 12
##### 9. Question

1 pointsThe population of a town has increased from 75000 to 78000. F What is the increased percentage of the town?

CorrectIncrease in population = 78000 – 75000 = 3000

Percentage increase = 3000/75000×100= 300/75=4%IncorrectIncrease in population = 78000 – 75000 = 3000

Percentage increase = 3000/75000×100= 300/75=4% - Question 10 of 12
##### 10. Question

1 pointsIn an election 5% of the total voters did take part. The candidate who was elected got 65% of the total votes. He got 3500 votes more that his opponent. Find the total number of voters.

CorrectLet the number of total voters = 100

Number of voters who did not take part in the election = 5

∴ Number of voters who took part in the election = 100 – 5 = 95

Number of votes secured by the elected candidate= 65% of 100 = 65

Number of votes secured by losing candidate = 95 – 65 = 30

∴Difference between the votes of the two candidate = 65 – 30 = 35

If difference in 35, the number of total votes = 100

If difference is 3500, the number of total votes= (100×3500)/35=10000IncorrectLet the number of total voters = 100

Number of voters who did not take part in the election = 5

∴ Number of voters who took part in the election = 100 – 5 = 95

Number of votes secured by the elected candidate= 65% of 100 = 65

Number of votes secured by losing candidate = 95 – 65 = 30

∴Difference between the votes of the two candidate = 65 – 30 = 35

If difference in 35, the number of total votes = 100

If difference is 3500, the number of total votes= (100×3500)/35=10000 - Question 11 of 12
##### 11. Question

1 pointsIn an local society membership election of two candidates, the candidate who gets 47% is rejected by a majority of 2730 votes. Find the total number of votes polled.

CorrectPercentage difference between candidate polled votes = (53% – 47%) = 6 %

As per the question;

candidate rejected by 6% of majority = 2730 votes

∴100% = 2730/6×100 = 45500 votesIncorrectPercentage difference between candidate polled votes = (53% – 47%) = 6 %

As per the question;

candidate rejected by 6% of majority = 2730 votes

∴100% = 2730/6×100 = 45500 votes - Question 12 of 12
##### 12. Question

1 pointsIf 2 liters of water are evaporated on boiling from 8 liters of sugar solution containing 5% sugar, find the percentage of sugar in the remaining solution.

Correct% of sugar in the original solution = 5% of 8 liters = 5/100×8 = 0.4%

After evaporation of 2 liters of water, the quantity of the remaining solution = 8 – 2 = 6 liters

∴The required percentage of sugar = 0.4/6×100% = 20/3%Incorrect% of sugar in the original solution = 5% of 8 liters = 5/100×8 = 0.4%

After evaporation of 2 liters of water, the quantity of the remaining solution = 8 – 2 = 6 liters

∴The required percentage of sugar = 0.4/6×100% = 20/3%